I don't know I don't have a coordinate plan
This question is incomplete, the complete question is;
Trevor is interested in purchasing the local hardware/electronic goods store in a small town in South Ohio. After examining accounting records for the past several years, he found that the store has been grossing over $850 per day about 60% of the business days it is open. Estimate the probability that the store will gross over $850 at least 6 out of 10 business day
Answer:
P( at least 6 out of 10 business days ) = 0.6312
Step-by-step explanation:
Given the data in the question;
p = 60% = 0.6
q = 1 - p = 1 - 0.6 = 0.4
Using Binomial distribution;
P( X = r ) =
where
we substitute
P( at leas 6 ) = P(6) + P(7) + P(8) + P(9) + P(10)
= [¹⁰C₆ × 0.6⁶ × 0.4⁴] + [¹⁰C₇ × 0.6⁷ × 0.4³] + [¹⁰C₈ × 0.6⁸ × 0.4²] + [¹⁰C₉ × 0.6⁹ × 0.4¹] + [¹⁰C₁₀ × 0.6¹⁰ × 0.4⁰]
= [0.250] + [0.214] + [0.1209] + [ 0.0403] + [ 0.00604 ]
= 0.6312
Therefore, P( at least 6 out of 10 business days ) = 0.6312
Answer:
4x + 6 = 38
Step-by-step explanation:
Substitute x in for x and see which equation is true
2x + 3 = 13
2*8+3 = 16+3 = 19 this is not 13 so it is false
4x + 6 = 38
4*8+6 = 32+6 = 38
This is true
3x - 5 = 29
3*8 -5 = 24-5 = 19
False
5x - 8 = 48
5*8-8 = 40-8 = 32
False
Answer:
1. 17/40
1. 0.425
1. 42.5%
2. 35/40
2. 0.875
2. 87.5%
Step-by-step explanation:
1. 17/401. 0.425 1. 42.5%2. 35/402. 0.8752. 87.5%
Answer:
32 divided by 4 would be 8
Step-by-step explanation: