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Katena32 [7]
3 years ago
11

Can you help me please

Mathematics
1 answer:
Setler [38]3 years ago
5 0
I think this question is a part of another question; you can have any ratio that can add up to 114 cm.
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A math instructor assigns a group project in each of the scenarios below, the instructor selects 5 consecutive students from thi
SVETLANKA909090 [29]

Complete question:

Consider a class of 20 students consisting of 5 sophomores, 8 juniors, and 7 seniors. A math instructor assigns a group project in each of the scenarios below, the instructor selects 5 consecutive students from this class, keeping track (in order) of the level of the student that he gets.

1a. How many possible outcomes are in the sample space S? (An outcome is a 5- tuple of students.)

Let A2 denote the event that exactly 2 of the selected students are sophomore, A5 denote the event that exactly 5 of the selected students are the juniors, and A4 denote the event that exactly 4 of the selected students are seniors.

1b. Find the probabilities of each of these three events. A2, A5, A4

1c. Do the events A2, A5, A4 constitute a partition of the sample space?

Answer:

Given:

n = 20

a) The possible outcome in the sample space,S, =

ⁿCₓ = ²⁰C₅

= \frac{20!}{(20-5)! 5!)}

= \frac{20*19*18*17*16}{5*4*3*2*1}

= 15504

b) probabilities of A2, A5, A4

P(A2) = ⁵C₂ / ²⁰C₂

= \frac{20}{320} = \frac{1}{19}

P(A5) = ⁸C₅ / ²⁰C₅

= \frac{56}{15540} = \frac{7}{1938}

P(A4) = ⁷C₄ / ²⁰C₄

= \frac{35}{4845} = \frac{7}{969}

c) No,the events A2, A5, A4, do not comstitute a partition of the sample space. i.e P(A2)+P(A5)+P(A4) ≠ 1

5 0
3 years ago
Please Help Me with these problems; Thank you. So much for the help.
stiks02 [169]
Answer to 1st one is d bottom right
2nd is b top right
5 0
3 years ago
PLS HELP!!
Arlecino [84]
It would be A 15 because you will have to take off 10 to make a square and then divide by 4 to get a square
6 0
3 years ago
Simplify (csc x)/(sec x)
Daniel [21]
\dfrac{\csc x}{\sec x}=\dfrac{\frac{1}{\sin x}}{\frac{1}{\cos x}}=\dfrac{\cos x}{\sin x}=\boxed{\cot x}
4 0
3 years ago
I WILL GIVE BRAINLY AS USUAL:Given that measure of angle 6 is 1/8 of measure of angle 4. Find the measures of these two angles i
victus00 [196]

Answer:

m∠4=160°

m∠6=20°

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

m∠6+m∠4=180° ----> equation A (by consecutive interior angles)

m∠6=(1/8)m∠4 ---> equation B

substitute equation B in equation A

(1/8)m∠4+m∠4=180°

Solve for m∠4

(9/8)m∠4=180°

m∠4=180°(8)/9

m∠4=160°

<em>Find the measure of m∠6</em>

m∠6=(1/8)m∠4

m∠6=(1/8)(160°)=20°

4 0
3 years ago
Read 2 more answers
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