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3 years ago

What are the x-intercepts of y=2x^2+6x-20?

Mathematics

2 answers:

goldfiish [28.3K]3 years ago

8 0

Answer:

The x-intercepts would be (2, 0) and (-5, 0).

Step-by-step explanation:

To find the x-intercepts, substitute in 0 for y and solve for x.

0 = 2x^2 + 6x - 20.

Solve the equation.

x = 2, -5.

NISA [10]3 years ago

7 0

Answer:

the x-intercepts are -5 and 2

Step-by-step explanation:

$y=2x^2+6x-20$

x-intercept is when y is set equal to zero

So, y = 0

$0 = 2x^2+6x-20$

$2x^3+6x-20 = 0\\Taking \ 2 \ common\\2(x^2+3x-10) = 0\\Dividing \ both \ sides \ by \ 2\\x^2+3x-10 = 0\\Using \ mid\ term \ break \ formula\\x^2+5x-2x-10 = 0\\x(x+5)-2(x+5)=0\\Taking \ (x+5) \ common\\(x+5)(x-2) = 0$

Either,

x+5 = 0 OR x-2 = 0

x = -5 OR x = 2

So, the x-intercepts are -5 and 2

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Answer

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1 year ago

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3 years ago

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Answer:

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