Question

Math SAT: Suppose the national mean SAT score in mathematics was 510. In a random sample of 50 graduates from Stevens High, the mean SAT score in math was 501, with a standard deviation of 30. Test the claim that the mean SAT score for Stevens High graduates is the same as the national average. Test this claim at the 0.10 significance level.(a) What type of test is this?(A) This is a left-tailed test.(B) This is a right-tailed test. (C) This is a two-tailed test.

Answer 1

Answer:

Mean SAT score for Stevens High graduates are not the same as the national average.    

Step-by-step explanation:

We are given the following information in question:

Population mean, μ = 510

Sample mean, $\bar{x}$ = 501

Sample size, n = 50

Alpha, α = 0.10

Sample standard deviation, s = 30

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 510\\H_A: \mu \neq 510$

We use Two-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n-1}} }$ Putting all the values, we have,

$t_{stat} = \displaystyle\frac{501 - 510}{\frac{30}{\sqrt{49}} } = -2.1$ Now,

$t_{critical} \text{ at 0.10 level of significance, 49 degree of freedom } = \pm 1.6765$ Since,              

$t_{stat} < t_{critical}$

We reject the null hypothesis and fail to accept it.

We accept the alternate hypothesis and mean SAT score for Stevens High graduates are not the same as the national average.