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Ratling [72]
3 years ago
5

about 0.6 of the human body is made up of water. if a person has a mass of 75 kilograms what is the mass of the water in this pe

rson body
Mathematics
2 answers:
Anna11 [10]3 years ago
6 0
45 kilograms of water is the mass
miv72 [106K]3 years ago
5 0

Answer:

45 kg of water

Step-by-step explanation:

About 0.6 of the human body is made up of water. if a person has a mass of 75 kilograms, we can find the mass of water by <em>multiplying the body mass (75 kg) by the fraction of water in the human body (0.6)</em>. That is,

75 kg × 0.6 = 45 kg

A 75 kg-person has about 45 kg of water.

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50 POINTS! Plot function h on the graph.<br><br> NO LINKS
tangare [24]

See attachment for the graph of the piecewise function h(x)

<h3>How to plot the function?</h3>

The function is given as:

h(x) = | -4,    x < 3

         | x + 5,    x >= 3

The above function is a piecewise function.

It has 2 separate functions at two domains

This means that we plot the sub-functions in the piecewise function at their respective domain

See attachment for the graph of the piecewise function h(x)

Read more about piecewise function at:

brainly.com/question/27262465

#SPJ1

3 0
1 year ago
<img src="https://tex.z-dn.net/?f=2a%20%7B%20%7D%5E%7B2%7D%20b%20%7B%7D%5E%7B2%7D%20-%207ab%20-%2030" id="TexFormula1" title="2a
yarga [219]

Answer:

(ab - 6)(2ab + 5)

Step-by-step explanation:

Assuming you require the expression factorised.

2a²b² - 7ab - 30

Consider the factors of the product of the coefficient of the a²b² term and the constant term which sum to give the coefficient of the ab- term

product = 2 × - 30 = - 60 and sum = - 7

The factors are - 12 and + 5

Use these factors to split the ab- term

= 2a²b² - 12ab + 5ab - 30 ( factor the first/second and third/fourth terms )

= 2ab(ab - 6) + 5(ab - 6) ← factor out (ab - 6) from each term

= (ab - 6)(2ab + 5) ← in factored form

5 0
3 years ago
Consider the following information related to a set of quantitative sample data:
svlad2 [7]

Answer:

(a) There are outliers

(b) x and x >62

Step-by-step explanation:

Given

\sigma = 14.92

\bar x = 22.0

q_0 = -24

q_1 = 14.5

q_2 = 24.5

q_3 = 33.5

q_4 = 64

Solving (a): Check for outliers

This is calculated using:

Lower = Q_1 - (1.5 * IQR) --- lower bound of outlier

Upper = Q_3 +(1.5 * IQR) --- upper bound of outlier

Where

IQR = Q_3 - Q_1

So, we have:

IQR = 33.5 - 14.5

IQR = 19

The lower bound of outlier becomes

Lower = Q_1 - (1.5 * IQR)

Lower = 14.5 - (1.5 * 19)

Lower = 14.5 - 28.5

Lower = -14

The upper bound of outlier becomes

Upper = Q_3 +(1.5 * IQR)

Upper = 33.5 + 1.5 * 19

Upper = 33.5 + 28.5

Upper = 62

So, we have:

-14 \le x \le 62 --- the range without outlier

Given that:

q_0 = -24  --- This represents the lowest data

q_4 = 64   --- This represents the highest data

-24 and 64 are out of range of -14 \le x \le 62.

Hence, there are outliers

Solving (b): The outliers

The outliers are data less than the lower bound (i.e. less than -14) or greater than the upper bound (i.e. 62)

So, the outliers are:

x and x >62

4 0
2 years ago
PLEASE HELP!!!!!!
Fofino [41]
It is 0.088 this is just for the 20 characters so dont read this fhehfhryhfrhuehhfuyrhuyhfhefheufrhfyer
4 0
3 years ago
Cancel subscription
anzhelika [568]

Answer:

What do you want answered?

5 0
2 years ago
Read 2 more answers
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