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qwelly [4]
3 years ago
8

20 Points h(n) = 2n - 4; Find h(1 + n)

Mathematics
2 answers:
grin007 [14]3 years ago
5 0

Answer:

2n-2

Step-by-step explanation:

h(n+1) = 2(n+1)-4

=2n+2-4

=2n-2

pentagon [3]3 years ago
4 0

Answer:

h(1 + n) = 2n - 2

Step-by-step explanation:

h(n) = 2n - 4 \\ h(1 + n ) = 2(1 + n) - 4 \\ h(1 + n) = 2 + 2n - 4 \\ h(1 + n) = 2n - 2

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Fifteen years ago, you deposited $12,500 into an investment fund. Five years ago, you added an
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Answer:

a) 8.16%

b) $65,762.50

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Step-by-step explanation:

Given:

15 years ago, Initial investment = $12500

5 years ago, Investment = $20000

Nominal interest = 8% semi annually for first 10 years

Interest2= 6.5% compunded annually for last five years

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EAR = [1 + (\frac{0.08}{2})]^2 - 1

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= (1.04)^2 - 1

= 1.0816 - 1

= 0.0816

= 8.16%

The effective annual interesting rate, EAR = 8.16 %

b) To find the amount in my account today.

Let's first find the amount for $12500 for 10 years compounded semi annually

= 12,500 +( 12,500 * 8.160% * 10)

= $ 22,700

Let's also find the amount for $32,500($12,500+$20,000) for 5 Years compoundeed annually

$32,500 + ($32,500 * 6.5% *5)

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Money in account today will be:

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Interest Amount = ( X * 8.160% * 10 ) = 0.8160 X

For next 5 years at 6.5%, we have:

Interest Amount = (X * 6.5% * 5) = 0.325 X

Therefore the total money at the end of 15 Years = 85000

0.8160X + 0.3250X + X = $85,000

= 2.141X = $85,000

X = 85,000/2.141

X = 39,701.074 ≈ $39,700

If I wish to have $85,000 now, I should have invested $39,700 15 years ago

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