Question

What will the reading on the Richter scale be for an earthquake that has an intensity of 3.8 × 10^6 and a reference value of 1? `(R = log (l/(l_0)))`

Answer 1

we are given

$I=3.8 \times 10^6$

$I_0=1$

now, we can use formula

$R=log(\frac{I}{I_0} )$

now, we can plug these values

we get

$R=log(\frac{3.8 \times 10^6}{1} )$

$R=6.57978$............Answer