(13 + 20) + 15 = 13 + (20 + 15)
Answer:
always true
Step-by-step explanation:
Given
2(x + 3) = 5x + 6 - 3x ← distribute left side
2x + 6 = 2x + 6
Since both sides are equal then any real value of x is a solution.
Thus the equation is always true
Answer:
= 1 5/16
[/tex] 1 \frac{5}{16}[/tex]
Step-by-step explanation:
![\frac{8}{5} (2x + 13) - 3 = 22](https://tex.z-dn.net/?f=%20%5Cfrac%7B8%7D%7B5%7D%20%282x%20%2B%2013%29%20-%203%20%3D%2022)
Expand
![\frac{16}{5} x + \frac{104}{5} - 3 = 22 \\ \frac{16}{5} x + \frac{89}{5} = 2](https://tex.z-dn.net/?f=%20%5Cfrac%7B16%7D%7B5%7D%20x%20%2B%20%20%5Cfrac%7B104%7D%7B5%7D%20%20-%203%20%3D%2022%20%5C%5C%20%20%5Cfrac%7B16%7D%7B5%7D%20x%20%2B%20%20%5Cfrac%7B89%7D%7B5%7D%20%20%3D%202)
Collect like terms and simplify
![\frac{16}{5} x = 22 - \frac{89}{5} \\ \frac{16}{5} x = \frac{21}{5}](https://tex.z-dn.net/?f=%20%5Cfrac%7B16%7D%7B5%7D%20x%20%3D%2022%20-%20%20%5Cfrac%7B89%7D%7B5%7D%20%20%5C%5C%20%20%5Cfrac%7B16%7D%7B5%7D%20x%20%3D%20%20%5Cfrac%7B21%7D%7B5%7D%20)
Cross Multiply
![80x = 105](https://tex.z-dn.net/?f=80x%20%3D%20105)
Divide both sides of the equation by 80
![\frac{80x}{80} = \frac{105}{80} \\ x = \frac{21}{16}](https://tex.z-dn.net/?f=%20%5Cfrac%7B80x%7D%7B80%7D%20%20%3D%20%20%5Cfrac%7B105%7D%7B80%7D%20%20%5C%5C%20x%20%3D%20%20%5Cfrac%7B21%7D%7B16%7D%20)
Answer: x=4,-4 Solve the equation for x by finding a, b, and c of the quadratic then applying the quadratic formula
Answer:
(cos^2 y) /(1-sin y) = (1 - sin^2 y) / (1-sin y) = ((1-sin y)(1+sin y)) / (1-sin y) = 1+sin y