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3 years ago

Silvia was growing some plants. She measured the height, in inches, of the plants and made thisline plot to show her data:

Mathematics

1 answer:

FromTheMoon [43]3 years ago

5 0

Answer:

The answer is C.

Step-by-step explanation:

The equivalents to 1/4 are 2/8, 3/12, 4/16 etc. So the fractions after 1/4 are higher than 1/4. Then you count how many 'x's are in the columns for those measurements and you will get 6.

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Find the number of ordered pairs $(m,n)$ of integers that satisfy \[mn = 2m + 4n.\] <img src="https://tex.z-dn.net/?f=Find%20the

Anna35 [415]

There are four pairs (m,n) that work: (5,10), (6,6), (8,4), and (12,3).

5 0

3 years ago

leah wrote two different fractions with the same denominator.both fractions were less than 1.can their sum equal 1? can their su

dem82 [27]

Their sum can be both equal, or greater. If you have 3/8 and 6/8, you would get 9/8 or 1 and 1/8. Which is greater than 1. Also if you add 2/6 and 4/6, you get 6/6 or 1. proving that both are possible.

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3 years ago

Let C = C1 + C2 where C1 is the quarter circle x^2+y^2=4, z=0,from (0,2,0) to (2,0,0), and where C2 is the line segment from (2,

trapecia [35]

Not much can be done without knowing what $\mathbf F(x,y,z)$ is, but at the least we can set up the integral.

First parameterize the pieces of the contour:

$C_1:\mathbf r_1(t_1)=(2\sin t_1,2\cos t_1,0)$
$C_2:\mathbf r_2(t_2)=(1-t_2)(2,0,0)+t_2(3,3,3)=(2+t_2, 3t_2, 3t_2)$

where $0\le t_1\le\dfrac\pi2$ and $0\le t_2\le1$ . You have

$\mathrm d\mathbf r_1=(2\cos t_1,-2\sin t_1,0)\,\mathrm dt_1$
$\mathrm d\mathbf r_2=(1,3,3)\,\mathrm dt_2$

and so the work is given by the integral

$\displaystyle\int_C\mathbf F(x,y,z)\cdot\mathrm d\mathbf r$
$=\displaystyle\int_0^{\pi/2}\mathbf F(2\sin t_1,2\cos t_1,0)\cdot(2\cos t_1,-2\sin t_1,0)\,\mathrm dt_1$
${}\displaystyle\,\,\,\,\,\,\,\,+\int_0^1\mathbf F(2+t_2,3t_2,3t_2)\cdot(1,3,3)\,\mathrm dt_2$

5 0

3 years ago

Find the two numbers whose sum is 29 and whose difference is 15.

yulyashka [42]

Answer:

a = 22

b = 7

Step-by-step explanation:

Let the two numbers be represented as a and b.

a + b = 29

a - b = 15

Using elimination method

Add both equations

2a = 44

Divide both sides by 2 to get a

2a/2 = 44/2

a = 22

Now substitute a = 22 in any of the equations to get b .

Using the first equation, we have

a + b = 29

22 + b = 29

Subtract 22 from both sides of the equation

22 - 22 + b = 29 - 22

b = 7

Therefore the two numbers are 22 and 7

7 0

3 years ago

Given sin x =-4/5 and x is in quadrent 3, what is the value of tan x/2

4vir4ik [10]

Answer:

We can write sin x in terms of tan x/2 using the formula:

⇒ sin x = (2 tan (x/2)) / (1 + tan2(x/2))

Therefore, using the above formula, we can find the values of tan x/2 by putting the value of sin x.

⇒ -4/5 = (2 tan (x/2)) / (1 + tan2(x/2))

Now, if we replace tan (x/2) by y, we get a quadratic equation:

⇒ 0.8y2 + 2y + 0.8 = 0

⇒ 2y2 + 5y + 2 = 0

By using the quadratic formula, we get y = -0.5, -2

Hence, the value of tan (x/2) = -0.5, -2

Now, we have two solutions of tan (x/2).

Now, let's check for the ideal solution using the formula tan x = (2 tan (x/2)) / (1 - tan2(x/2)).

For tan (x/2) = -0.5:

⇒ tan x = 2(-0.5) / 1 - (-0.5)2 = -4/3

It is also given that x lies in the third quadrant. We know that tan is positive in the third quadrant, and here we get tan x = -4/3 which is negative.

Hence, we can say that tan (x/2) = -0.5 is not a correct solution. Hence it is rejected.

Now let's check for tan (x/2) = -2.

⇒ tan x = 2(-2) / 1 - (-2)2 = 4/3

Here, we get tan x = 4/3 which is positive.

Hence, we can say that tan (x/2) = -2 is a correct solution.

5 0

3 years ago