Answer:
On average, cars enter the highway during the first half hour of rush hour at a rate 97 per minute.
Step-by-step explanation:
Given that, the rate R(t) at which cars enter the highway is given the formula

The average rate of car enter the highway during first half hour of rush hour is the average value of R(t) from t=0 to t=30.

![=[100(t-0.0001\frac{t^3}{3})]_0^{30}](https://tex.z-dn.net/?f=%3D%5B100%28t-0.0001%5Cfrac%7Bt%5E3%7D%7B3%7D%29%5D_0%5E%7B30%7D)
![=100[(30-0.0001\frac{30^3}{3})-(0-0.0001\frac{0^3}{3})]](https://tex.z-dn.net/?f=%3D100%5B%2830-0.0001%5Cfrac%7B30%5E3%7D%7B3%7D%29-%280-0.0001%5Cfrac%7B0%5E3%7D%7B3%7D%29%5D)
=2901
The average rate of car is 

=97
On average, cars enter the highway during the first half hour of rush hour at a rate 97 per minute.
The answer for your question is thirteen
Answer:
True
Step-by-step explanation:
<span>3/5 + 3/7
Multiply the denominator until they have the same common denominator.
21/35 + 15/35
Add the numerators but NOT the denominators
Final Answer: 36/35 or 1 1/35</span>
3x+4y = 375
6x+ 4y= 600
-------------------
6x-3x = 600 - 375
3x=225
x=225:3
x=75 cents
3*x+4y= 375
3*75+4y=375
225 +4y = 375
4y=375-225
4y=150
y=150:4
y=37,5 cents
the price is 75+37,5=112,5 cents for one bag of potato chips and one candy bar