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lora16 [44]
3 years ago
5

Quick question plz help ASAP!

Mathematics
1 answer:
Pie3 years ago
7 0

Answer:

84°

Step-by-step explanation:

m∠TRV=2*m∠TUV;

m∠TRV=42*2=84°.

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observa con atencion los siguientes desarrollos planos y encierra con cual de ellos se puede armar cada cuerpo uno de ellos tien
Viefleur [7K]

Answer:

Can you give it in a english

Step-by-step explanation:

7 0
3 years ago
The cost of one pound of bananas is greater than $0.41 and less than $0.50. Sarah pays $3.40 for x pounds of bananas. Which ineq
vredina [299]

Answer:

0.41<3.40/x<0.50

Step-by-step explanation:

Given that the cost of one pound of bananas is greater than $0.41 and less than $0.50. That is,

If the cost of one banana is P, then, the inequality will be

0.41 < P < 0.50

Sarah pays $3.40 for x pounds of bananas. The inequality that represents the range of possible pounds purchased will be achieved by below

3.40/0.41 = 8.29

3.40/0.50 = 6.8

Therefore, the inequality that represents the range of possible pounds purchased is

6 < x < 9 this is the same as 0.41<3.40/x<0.50

6 0
3 years ago
The mass of a grain of dad is 10^-3 grams. about how many grams of sand are in a 10kg bag of sand.
Mashutka [201]
98-787 eng 676 #56 is done 
4 0
4 years ago
What do you predict the solution for the system 5x-6y=7 and 6x-7y=8 will be ?<br>​
Alenkinab [10]
System of Linear Equations entered :

[1] 5x - 6y = 7
[2] 6x - 7y = 8
Graphic Representation of the Equations :

-6y + 5x = 7 -7y + 6x = 8

Solve equation [2] for the variable x


[2] 6x = 7y + 8

[2] x = 7y/6 + 4/3
// Plug this in for variable x in equation [1]

[1] 5•(7y/6+4/3) - 6y = 7
[1] - y/6 = 1/3
[1] - y = 2
// Solve equation [1] for the variable y


[1] y = - 2
// By now we know this much :

x = 7y/6+4/3
y = -2
// Use the y value to solve for x

x = (7/6)(-2)+4/3 = -1
8 0
3 years ago
Find center and radius<br> (x-3)^2+y^2=8
Flauer [41]

Answer:

<h2>Center: (3, 0)</h2><h2>Radius: 2√2</h2>

Step-by-step explanation:

The equation of a circle in standard form:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have the equation:

(x-3)^2+y^2=8\to(x-3)^2+(y-0)^2=(\sqrt8)^2

Therefore

the center: (3,\ 0)

the radius: r=\sqrt8\to r=\sqrt{4\cdot2}\to r=\sqrt4\cdot\sqrt2\to r=2\sqrt2

4 0
3 years ago
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