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klio [65]
3 years ago
12

Which pair of atoms has the highest electronegativity difference?

Chemistry
1 answer:
finlep [7]3 years ago
3 0
I'll go through them one by one
1) H-S
The electronegativity of Hydrgoen is 2.2, and sulphur is 2.58,
therefore the difference is 0.38 (2.58-2.2=0.38)
2) H-Cl
Hydrogen: 2.2, Chlorine: 3.16
therefore difference is 0.96
3) N-H
Nitrogen: 3.04, Hydrogen: 2.2
therefore difference is 0.84
4) C-H
Carbon: 2.55, hydrogen: 2.2
therefore difference is 0.35

so, the most apparent electronegativity is chlorine, but this could have been done without actually doing the maths. The trend of electronegativty increases across a period and increases up a period due to the strong affinity of the nucleus with bonding electrons. This does not include noble gases though, as they have no charge due to having complete valance shells. T<span>he most electronegative element is Fluorine (9), and the least electronegative element (besides noble gases) is Francium (87)</span>
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Explanation:

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I NEED ANSWER ASAP Which of the following statements is true for a scientific theory? It is a well-tested hypothesis. It is veri
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What is the value for the reaction: N2(g) + 2 O2(g) --&gt; N2O4(g) in terms of K values from the reactions:
Valentin [98]

Answer : The correct expression will be:

K=(K_1)^2\times K_2

Explanation :

The chemical reactions are :

(1) \frac{1}{2}N_2(g)+\frac{1}{2}O_2(g)\rightleftharpoons NO(g) K_1

(2) 2NO(g)+O_2(g)\rightleftharpoons N_2O_4(g) K_2

The final chemical reaction is :

N_2(g)+2O_2(g)\rightleftharpoons N_2O_4 K=?

Now we have to calculate the value of K for the final reaction.

Now equation 1 is multiply by 2 and then add both the reaction we get the value of 'K'.

If the equation is multiplied by a factor of '2', the equilibrium constant will be the square of the equilibrium constant of initial reaction.

If the two equations are added then equilibrium constant will be multiplied.

Thus, the value of 'K' will be:

K=(K_1)^2\times K_2

6 0
3 years ago
What is the energy of a wave with wavelength of 4.2 x 10-7 m. (Hint: Calculate for frequency first.)
erik [133]

Answer:

Option B. 4.74×10¯¹⁹ J.

Explanation:

The following data were obtained from the question:

Wavelength (λ) = 4.2×10¯⁷ m

Energy (E) =.?

Next, we shall determine the frequency of the wave. This can be obtained as follow:

Wavelength (λ) = 4.2×10¯⁷ m

Velocity (v) = constant = 3×10⁸ m/s

Frequency (f) =.?

v = λf

3×10⁸ = 4.2×10¯⁷ × f

Divide both side by 4.2×10¯⁷

f = 3×10⁸ / 4.2×10¯⁷

f = 7.143×10¹⁴ s¯¹

Therefore, the frequency of the wave is 7.143×10¹⁴ s¯¹.

Finally, we shall determine the energy of the wave using the following formula

E = hf

Where

E is the energy.

h is the Planck's constant

f is the frequency

Thus, the enery of the wave can be obtained as follow:

Frequency (f) = 7.143×10¹⁴ s¯¹.

Planck's constant = 6.63×10¯³⁴ Js

Energy (E) =..?

E = hf

E = 6.63×10¯³⁴ × 7.14×10¹⁴

E = 4.74×10¯¹⁹ J

Therefore, the energy of the wave is 4.74×10¯¹⁹ J.

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What process takes place when hydrogen-3 and hydrogen-2 combine to form
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Answer:

A. Fusion

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