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likoan [24]
4 years ago
12

Can the cube of an integer be a negative number

Mathematics
2 answers:
andreyandreev [35.5K]4 years ago
7 0
The answer would be yes because if you take a negative number say, -10 and take it to the power of 3 (cub(e)(ing)) -10^3 you have to take -10* itself 3 times and when you do that the first time that you do that you get this -10*-10=100 but them you still have to times it by -10 one more time because its a cube((-e)ing) meaning 3 so we take it times -10 once more and we get are end answer of 100*-10=-1000.
So to answer your question yes it is possible in a cubing now if this was a squaring then no because a negaive time a negative is always a positive.

Enjoy!=)
JulijaS [17]4 years ago
7 0
Yes.  The cube of a negative number is negative.  For example, -1^3=-1*-1*-1=-1, which is negative.
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3 years ago
How would I do this question.
olga2289 [7]

Answer:

The density of cube is 6.17959 \frac{g}{cm^{3} }

Step-by-step explanation:

The density is given by ration of a mass of body and volume occupied by a body.

\rho = \frac{m}{V}

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m is mass of a body

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Given that one side of the cube is 0.53cm

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3 0
3 years ago
Lydia graphed ΔXYZ at the coordinates X (0, −4), Y (2, −3), and Z (2, −6). She thinks ΔXYZ is a right triangle. Is Lydia's asser
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Answer:

Option (4)

Step-by-step explanation:

Vertices of the triangle are X(0, -4), Y(2, -3) and Z(2, -6).

Slope of XY (m_{1}) = \frac{y-y'}{x-x'}

                            = \frac{-3+4}{2-0}

                     (m_{1}) = \frac{1}{2}

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m_{1}\times m_{2}=-\frac{1}{2}

Which should be (-1) if XY and XZ are perpendicular to each other.

Now we can say that XY and XZ are not perpendicular.

Therefore, Lydia's assertion that ΔXYZ is a right triangle is not correct.

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