Answer:
first triangle (to left) b=8, second one c=17
Step-by-step explanation:
for the first triangle (one to the left) the hypotenuse is 9, so let's use the pythagorean formula.
A^2 + B^2 = C^2
^ ^ ^
^ ^ Hypotenuse
^ second side
first side
Substitute:
5^2 + b^2 = 9^2
SImplify:
25+b^2 = 81
Reduce:
b^2 = 64
Simplify:
b=8
In the second triangle, we are given 2 sides.
Let's do the same thing we did in the first one.
Givens:
A = 8
B = 15
Find:
C
Substitute:
8^2 + 15^2 = c^2
Simplify
64 + 225 = c^2
Reduce:
289 = c^2
Let's now square root both sides
square root of 289 is 17
so we are left with this:
c=17
Phew, you did it!
Hope this helped :))
Answer:
Option C.
Step-by-step explanation:
Consider the complete question is "Triangle JKL is transformed using the rule 
. Point K of the pre-image is at (4, 7). What are the coordinates of point K'' on the final image?".
According to 
, we get
According to 
, we get
The rule means first reflection and then rotation.
We need to find the image of K(4,7).
After reflection, we get
After rotation, we get
Therefore, the correct option is C.
Answer:
You need to have an attachment or question for us to help you. :3
Step-by-step explanation:
$5.25, because if you multiply $6 by 7/8(fraction form), you get $5.25
