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vovikov84 [41]
3 years ago
12

Write 3x^2+7x+2 in the form of a(x-h)^2+k

Mathematics
1 answer:
sertanlavr [38]3 years ago
3 0

Answer:

y = 3(x+7/6)² - 25/12

Step-by-step explanation:

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Explain how to find the estimated sum of 5/8+2/9 . Make sure to include at least one type of model.
OverLord2011 [107]
In this expression you would have to use the PEMDAS method. First divide, so (5 divided by 8) + (2 divided by 9). 
The answer you would get is: (0.625) + (0.222)
The final answer is: 0.847

8 0
3 years ago
If the area of the square is A(s) = s², find the formula for the area as a function of time, and then determine A(s(3)).
Oxana [17]

A(t) = 100t^2 + 500t + 625

3,025 square pixels

5 0
3 years ago
Read 2 more answers
The product of two mixed numbers x and y is 10. If x= _ 2/3 and y=_ 3/4 ,<br> find x and y?
Akimi4 [234]

Answer:

  • x = 2 2/3
  • y = 3 3/4

Step-by-step explanation:

There may be other ways to do this. Here's the approach I took. Let the integer part of x be represented by "a", and the integer part of y be represented by "b". Now, we have ...

  (a +2/3)(b +3/4) = 10

Multiplying by 12, this becomes ...

  (3a +2)(4b +3) = 120

There are only 16 divisors of 120, so they can be easily enough checked one at a time.

  120 = 1·120 = 2·60 = 3·40 = 4·30 = 5·24 = 6·20 = 8·15 = 10·12

Of these divisors, the ones that are of the form 3a+2 are ...

  2, 5, 8, 20 . . . . a=0, 1, 2, 6

The ones that are of the form 4b+3 are ...

  3, 15 . . . . b = 0, 3

The factor pair that consists of a number on the first list and a number on the second list is ...

  120 = 8·15

corresponding to a=2 and b=3. So, the mixed numbers you want are ...

  x = 2 2/3

  y = 3 3/4

_____

<em>Check</em>

  (2 2/3)·(3 3/4) =2·3 +2·3/4 +2/3·3 +2/3·3/4 = 6 +6/4 +2 +2/4 = 8+8/4 = 10

6 0
3 years ago
The length and width of a rectangle are measured as 31 cm and 28 cm, respectively, with an error in measurement of at most 0.1 c
MissTica

Answer:

\Delta A = 5.9\,cm^{2}

Step-by-step explanation:

The area of an rectangle is given by the following formula:

A = w\cdot h

Where:

w - Width, in centimeters.

h - Height, in centimeters.

The differential of the expression is derived hereafter:

\Delta A  = \frac{\partial A}{\partial w} \cdot \Delta w + \frac{\partial A}{\partial h}\cdot \Delta h

\Delta A = h \cdot \Delta w + w \cdot \Delta h

\Delta A = (31\,cm)\cdot (0.1\,cm) + (28\,cm)\cdot (0.1\,cm)

\Delta A = 5.9\,cm^{2}

5 0
3 years ago
Find three consecutive integers such that the sum of the first and twice the second is 80 minus three times the third
ivanzaharov [21]

Answer:

The three consecutive integers are 12, 13, 14.

Step-by-step explanation:

Encode the question in an equation. We are given two facts: (1) the three integers are consecutive, and (2) they relate to each other through a sum.

Pick any of the integers (first, second, or third) and call it n. Then write the two others correspondingly in terms of n. I pick the middle one as n, so the three consecutive integers are (n-1), n, (n+1). That's (1). As for (2), here is the fact:

(n-1)+2n = 80-3(n+1)

Lo and behold, one equation with one unknown! Easy to solve for n to give us  the middle integer, n:

(n-1)+2n = 80-3(n+1)\\3n-1= 80-3n -3\\6n =78\\n = 13

The three consecutive integers are 12, 13, 14.

3 0
4 years ago
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