You would do three square in length and 31 in width
The solutions to the questions are given below
a)
sample(n) word length sample mean
1 5,4,4,2 3.75
2 3,2,3,6 3.5
3 5,6,3,3 4.25
b)R =0.75
c)
- The mean of the sample means will tend to be a better estimate than a single sample mean.
- The closer the range of the sample means is to 0, the more confident they can be in their estimate.
<h3>What is the students are going to use the sample means to estimate the mean word length in the book.?</h3>
The table below shows sample means in the table.
sample(n) word length sample mean
1 5,4,4,2 3.75
2 3,2,3,6 3.5
3 5,6,3,3 4.25
b)
Generally, the equation for is mathematically given as
variation in the sample means
R =maximum -minimum
R=4.25-3.5
R =0.75
c)
In conclusion, In most cases, the mean of many samples will provide a more accurate estimate than the mean of a single sample.
They may have a higher level of confidence in their estimate if the range of the sample means is closer to 0 than it is now.
Read more about probability
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Answer:
FALSE
Step-by-step explanation:
In order to be consistent with the system of unit we should decide if we are going to work with the CGS system <em>(centimeter-gram-second)</em> or the MKS system <em>(meter-kilogram-second).
</em>
If we decide to work with the CGS system, the equation of motion would be
8,000x ′′ + 2x = 0; x(0) = 3, x ′ (0) = 0
since 1 Kg = 1,000 g
If we decide to work with the MKS system, the equation of motion would be
8x ′′ + 2x = 0; x(0) = 0.03, x ′ (0) = 0
given that 1 mt = 100 cm
The acceleration is 10 because 50 divided by 5 is 10.
