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3 years ago

HELP pls What is the equation for the line? Enter your answer in the box.

Mathematics

1 answer:

FrozenT [24]3 years ago

8 0

Answer:

y=8x

Step-by-step explanation:

To find the slope, or m, pick 2 points.

I chose (0, 0) and (2, 16)

The use the slope formula

16-0/2-0

16/2

to find the y-intercept, or b, find the point where the line crosses the y-axis, which is (0, 0). Take the y-coordinate, which is 0.

So,

y=8x+0

or y=8x

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Graph of g(x) = x2 − 5

Brut [27]

Answer: 6rx = x^2 -5

8 0

3 years ago

Find the surface area of the solid generated by revolving the region bounded by the graphs of y = x2, y = 0, x = 0, and x = 2 ab

Nikitich [7]

Answer:

See explanation

Step-by-step explanation:

The surface area of the solid generated by revolving the region bounded by the graphs can be calculated using formula

$SA=2\pi \int\limits^a_b f(x)\sqrt{1+f'^2(x)} \, dx$

If $f(x)=x^2,$ then

$f'(x)=2x$

and

$b=0\\ \\a=2$

Therefore,

$SA=2\pi \int\limits^2_0 x^2\sqrt{1+(2x)^2} \, dx=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx$

Apply substitution

$x=\dfrac{1}{2}\tan u\\ \\dx=\dfrac{1}{2}\cdot \dfrac{1}{\cos ^2 u}du$

Then

$SA=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx=2\pi \int\limits^{\arctan(4)}_0 \dfrac{1}{4}\tan^2u\sqrt{1+\tan^2u} \, \dfrac{1}{2}\dfrac{1}{\cos^2u}du=\\ \\=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0 \tan^2u\sec^3udu=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0(\sec^3u+\sec^5u)du$

Now

$\int\limits^{\arctan(4)}_0 \sec^3udu=2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17})\\ \\ \int\limits^{\arctan(4)}_0 \sec^5udu=\dfrac{1}{8}(-(2\sqrt{17}+\dfrac{1}{2}\ln(4+\sqrt{17})))+17\sqrt{17}+\dfrac{3}{4}(2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17}))$

Hence,

$SA=\pi \dfrac{-\ln(4+\sqrt{17})+132\sqrt{17}}{32}$

3 0

3 years ago

Witch of these has a slope of -3/4 and a y intercept of 3/2

Arada [10]

Answer:

See explanation. (Also you can write an equation several different ways so without the choices I cannot tell you which)

Step-by-step explanation:

Slope-intercept form is y=mx+b

So one way to write the equation is y=-3/4 x +3/2

There are more ways to write it.

Every line about to write is a way to write it.

Multiply both sides by 4: 4y=-3x+6

Add 3x on both sides: 3x+4y=6

Subtract 6 on both sides: 3x+4y-6=0

There are a lot of ways to write an equation like this.

To better assist you I would need to see options.

5 0

3 years ago

Express this number in standard form. 1.588 \times 10^{-1} = {?}1.588×10 −1 =?

Hunter-Best [27]

1.5879

1.588 times 10q.

3 0

3 years ago

What is the equation of the line shown in this graph? any links will be reported

Blizzard [7]

Answer:

y = 1

Step-by-step explanation:

Slope is written in the form y=mx+b. Where m is the slope and b is the y-intercept.

When there isn't a slope, as in the line is flat and it isn't moving up or down, you wouldn't write anything for it. You would just write y equals the y-intercept (y = b).

Likewise, if the y-intercept is at (0,0), then you'd only write y equals the slope (y = mx).

Hopefully this makes sense :)

Btw, I also answered in the main comments earlier, so you can check that out as well.

7 0

2 years ago