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snow_tiger [21]
3 years ago
15

Solve for m p=3rmv^2

Mathematics
1 answer:
juin [17]3 years ago
7 0
Let’s Solve for m

p=3rmv^2

Step 1 Flip the equation

3mrv^2=p

Step 2 Divde Both Sides by 3rv^2

3mrv^2/3rv^2=p/3rv^2

m=p/3rv^2

ANSWER

m=p/3rv^2
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Identify the area of segment MNO to the nearest hundredth. HELP PLEASE!! I don't understand it!
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Answer:

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Step-by-step explanation:

I don't understand it, either.

Point N is part of a "segment" that above and to the right of chord MO. It is the sum of the areas of 3/4 of the circle and a right triangle with 7-inch sides. The larger segment MO to the upper right of chord MO has an area of about 139.95 in², which <u>is not</u> an answer choice.

__

The remaining segment, to the lower left of chord MO does not seem to have anything to do with point N. However, its area is 13.98 in², which <u>is</u> an answer choice. Therefore, we think the question is about this segment, and we wonder why it is called MNO.

The area of a segment is given by the formula ...

  A = (1/2)(θ -sin(θ))r² . . . . . . where θ is the central angle in radians.

Here, we have θ = π/2, r = 7 in, so we can compute the area of the smaller segment MO as ...

  A = (1/2)(π/2 -sin(π/2))(7 in)² = 24.5(π/2 -1) in² ≈ 13.9845 in²

Rounded to hundredths, this is ...

  ≈ 13.98 in²

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Step-by-step explanation:

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