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timama [110]
3 years ago
12

A group of 18 people ordered soup and sandwiches for lunch. Each person in the group either ordered one soup or one sandwich . T

he sandwiches cost $7.75 and the soup cost $4.50 if the total cost of all the food was $113.50 how many sandwiches where ordered?
Mathematics
1 answer:
kkurt [141]3 years ago
8 0
Let's say a = number of ordered soups, b = number of ordered sandwiches.

Then 4.5a + 7.75b = 113.50, and a and b are integers between 0 and 18 inclusive.

How do we tackle this? If all ordered soup, the cost would be $81, so we'll have at least 4 sandwiches. If all ordered sandwich, the cost would be $139.5, so at most 15 sandwiches were ordered. You also know an even number of sandwiches was ordered, to let the price end at 50 cent.

If you brute-force from 4,6,8,10,12 to 14 sandwiches, you find the answer at 10 sandwiches and 8 soups.

10*7.75 + 8*4.50 = 113.50


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5 0
3 years ago
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13. Ruby deposited $1,200 in an account that pays 5% in simple interest.
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5 0
3 years ago
What is the following quotient?
almond37 [142]

Answer:

B)  \sqrt{30}  - 3 \sqrt{2}  +  \sqrt{55}  -  \sqrt{33}  \div 2

Step-by-step explanation:

Step 1: First we have to get rid off the roots in the denominator.

To do that, we have to multiply the numerator and the denominator by the conjugate of √5 + √3.

The conjugate of √5 + √3 is √5 - √3.

Now multiply given expression with √5 - √3

(√6 + √11)     (√5 - √3)

------------- x   -----------

(√5 + √3)        (√5 - √3)

Step 2: Multiply the numerators and the denominators.

√6√5 - √6√3 +√11√5 -√11√3

------------------------------------------

(√5)^2 - (√3)^2

Now let's simplify to get the answer.

√30-√18 +√55 - √33

-----------------------------

5 - 3

= √30 -3√2 +√55                                     [√18 = √9√2 = 3√2]

--------------------------

2      

The answer is  \sqrt{30}  - 3 \sqrt{2}  +  \sqrt{55}  -  \sqrt{33}  \div 2


Thank you.

4 0
3 years ago
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