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Neporo4naja [7]
4 years ago
11

The sides of a rectangle are 15cm and 7cm long. How far is the point of the diagonal cross section from the sides of this rectan

gle?
please include explanation ​
Mathematics
1 answer:
irinina [24]4 years ago
6 0

Answer:

See below in bold.

Step-by-step explanation:

If we draw a line from the point of intersection to the longest side of the rectangle it will meet it at the midpoint.

The same thing will happen when the line is draw to the shortest side.

So the point of intersection is  1/2 * 7 = 3.5 cm from the longest side and 15/2 = 7.5 cm from the shortest side.

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Answer:

Given: △ABC, m∠B=90° AB=12, BC=16, BK ⊥ AC . Find: AC and BK.

Given: △ABC, m∠B=90°

Find: AC and BK.

Short leg 90 degrees Long leg Hypotenuse

AB=12 90 BC=16 AC= ?

AK = ? 90 BK = ? AB=12

AC = SQRT (AB*AB + BC*BC) = 20 [right triangle; Pythagorean Theorem]

Similar triangles:[Note: In diagram, share two angles. Therefore share three angles]

BK / 16 = AB / AC

BK / 16 = 12 / 20

BK = (3/5)16

BK = 48/5

another answer let see this

AB^2+BC^2=AC^2

12^2+16^2=AC^2

144+256=AC^2

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20=AC

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