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VMariaS [17]
3 years ago
9

lihzi and hiro order pizzas for a party for 10 members of the chess team.the team pays $60 for the pizzas.if 8 team members each

pay an equal share,and lihzi and hiro each pay double that amount,how much does each of the other 8 members pay?how much do lihzi and hiro each pay?
Mathematics
1 answer:
alexandr402 [8]3 years ago
6 0
Heya!!!

Answer is....

let x be the amont of money given by 8 members each.
therefore, hiro and lihzi gives $2x.

A.T.Q.



8x+2 (2x)=60

8x+4x=60

12x=60

x=60/12

x=5

each of 8 members paid $5.

lihzi and hiro paid $10.



HOPE IT HELPS YOU '_'
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Answer:

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Step-by-step explanation:

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Therefore using given data: Mu = 14, SD = 1.2 we have z(x) by using z(x) = (x - Mu)/SD as under:

Approach 1 using Standard Normal Distribution Table:

z for x=17: z(17) = (17-14)/1.2 gives us z(17) = 2.5

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Afterwards using Normal Distribution Tables we find the probabilities as under:

P(17) using z(17) = 2.5 gives us P(17) = 99.379%

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P(13) using z(13) = -0.83 gives us P(13) = 20.327%

Finally in order to find out the probability between 17 & 13 years we have:

Percentage of armadillos between 13 and 17 years = P(17) - P(13) = 99.379% - 20.327% = 79.052%

The standard normal distribution table is being attached for yours easiness.

Approach 2 using Excel or Google Sheets:

P(17) = norm.dist(17,14,1.2,1)

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