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Tcecarenko [31]
3 years ago
15

Triangle ABC and triangle CDE are similar right triangles. Which proportion can be used to show that the slope of AC is equal to

the slope of CE?
A.6-3 3-(-3)
-3-1 -1-3

B.6-3 3-3
-3-(-1) -1-3

C.6-3 3-(-3)
-3-(-1) -1-3

D.-3-(-1) 3-(-3)
6-3 -1-3​

Mathematics
2 answers:
BabaBlast [244]3 years ago
5 0

Answer:

     

Step-by-step explanation:

Marianna [84]3 years ago
4 0

Answer:

C.

(6 - 3)/(-3 - (-1))

(3 - (-3))/(-1 - 3)= 6/(-4)

Step-by-step explanation:

Slope AC = (y(A) - y(C))/(x(A) - x(C)) = (6 - 3)/(-3 - (-1)) = 3/(-2)

Slope CE = (y(C) - y(E))/(x(C) - x(E)) = (3 - (-3))/(-1 - 3)= 6/(-4) = 3/(- 2)

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Answer:

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The "average value of function f(x) on interval [a, b] is given by:

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ave. value = ---------------

                         b - a

Here f(t)=(t-2)^2.

Thus, f(b) = (b - 2)^2.  For b = 6, we get:

          f(6) = 6^2 - 4(6) + 4, or f(6) = 36 - 24 + 4 = 16

For a = 0, we get:

           f(0) = (0 - 2)^2 = 4

Plugging these results into the ave. value function shown above, we get:

                      16 - 4

ave. value = ------------ = 12/6 = 2

                         6 - 0

The average value of the function f(t)=(t-2)^2 on [0,6] is 2.


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