Ask question

Ask question

All categories

3 years ago

15

the line represented by the equation 4y=3x+7 is transformed by a dilation centered at the origin. Which linear equation could re

present its image? 1) 3x-4y=9. 2) 3x+4y=9. 3) 4x-3y=9. 4) 4x+3y=9.

2 answers:

krok68 [10]3 years ago

7 0

Answer:

3x-4y=9

Step-by-step explanation:

KatRina [158]3 years ago

4 0

Why is this so hard i cant even solve it i need someone to answer this to

You might be interested in

Help !<br><br> 174 > 26.6 + 8.5n

Mekhanik [1.2K]

566353621818281727.1232321.2.23121232132312>3454535435454/.435

3 0

2 years ago

What is the value of X

AleksandrR [38]

Well you see here, you need to take attest pre-calculus to answer this question. I am in 6th grade.

7 0

3 years ago

The perimeter of a rectangle is 66 feet. The width is 15 ft less than 1/2 the length. Find the dimensions of the figure

lianna [129]

The length is 32 and the width is 1. 32÷2 is 16. 16-15 is 1. 32+32+1+1 is 66

8 0

3 years ago

A bridge in the shape of an arch connects two cities separated by a river. The two ends of the bridge are located at (–7, –13) a

sdas [7]

Answer:

$y=-\dfrac{13}{49}x^2$

Step-by-step explanation:

The shape of an arch corresponds to a parabola.

the general equation for a parabola is:

$y=ax^2+bx+c$

we're given three coordinates: (-7,-13),(7,-13) and (0,0)

so we can plug these values in the general equation to make 3 separate equations:

(x,y) = (-7,-13)

$-13=a(-7)^2+b(-7)+c$

$49a-7b+c=-13$

(x,y) = (7,-13)

$-13=a(7)^2+b(7)+c$

$49a+7b+c=-13$

(x,y) = (0,0)

$0=a(0)^2+b(7)+c$

$c=0$

so we have three equations. and we can solve them simultaneously to find the values of a,b, and c.

we've already found c = 0, let's use substitute it to other equations.

$49a-7b+c=-13\quad\Rightarrow\quad49a-7b=-13$

$49a+7b+c=-13\quad\Rightarrow\quad49a+7b=-13$

we can solve these two equation using the elimination method, by simply adding the two equations

$\quad\quad49a-7b=-13\\+\quad49a+7b=-13$

------------------------------

$\quad\quad 98a=-26$

$\quad\quad a=-\dfrac{13}{49}$

Now we can plug this value of a in any of the two equations.

$49a-7b=-13$

$49\left(-\dfrac{13}{49}\right)-7b=-13$

$-13-7b=-13$

$-7b=0$

$b=0$

We have the values of a,b, and c. We can plug them in the general equation to find the equation of the arch.

$y=\left(-\dfrac{13}{49}\right)x^2+0x+0$

$y=-\dfrac{13}{49}x^2$

$49y=-13x^2$

This our equation of the arch!

5 0

3 years ago

Four friends share 3535 of a rectangular pizza .What fraction of the pizza did each receive?

Gwar [14]

Answer:

$\frac{35}{4} or 8\frac{3}{4}$

6 0

3 years ago