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4 years ago

14

Solve by using the perfect squares method.* x2 – 12x + 36 = 0

2 answers:

ElenaW [278]4 years ago

4 0

$x^2 -12x + 36 = 0\\ \\ (x-6)^2= 0 \\ \\ x-6=0 \\ \\ x=6$

Vedmedyk [2.9K]4 years ago

4 0

X2 - 12x + 36 = 0
x2 - 2*x*6 +6^2 = 0
(x-6)^2 = 0
x-6 = 0
x = 6

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