Answer:
Probability that two or more of them have Type A blood is 0.6242.
Step-by-step explanation:
We are given the approximate probabilities that a person will have blood type O, A, B, or AB.
<u>Blood Type</u> O A B AB
<u>Probability</u> 0.4 0.2 0.32 0.08
A group of 10 people are chosen randomly.
The above situation can be represented through Binomial distribution;
where, n = number of trials (samples) taken = 10 people
r = number of success = two or more have Type A blood
p = probability of success which in our question is probability
that a person has Type A Blood, i.e; p = 20% or 0.20
<em>LET X = Number of person having Type A Blood</em>
So, it means X ~ Binom(n = 10, p = 0.20)
Now, Probability that two or more of them have Type A blood is given by = P(X 2)
P(X 2) = 1 - P(X = 0) - P(X = 1)
=
=
= 0.6242
<em>Hence, the probability that two or more of them have Type A blood is 0.6242.</em>