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konstantin123 [22]
3 years ago
8

Amembers-onlyspeakerseriesallowspeopletojoinfor

Mathematics
1 answer:
ira [324]3 years ago
6 0

Answer: 1.5

Step-by-step explanation:

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The 95% confidence interval for a population mean (context unknown and irrelevant) turns out to be (428, 510). What is E?
Elina [12.6K]

The 95% confidence interval for a population mean has a margin of error (E) of 41

The confidence interval for a population mean is given by:

Confidence interval = μ ± E = (μ - E, μ + E)

Where μ is the mean and E is the margin of error.

Since the confidence interval is (428, 510), hence:

μ - E = 428      (1)

μ + E =  510     (2)

Subtracting equation 1 from equation 2:

2E = 82

E = 41

μ - E = 428

μ -41 = 428

μ = 469

Hence the margin of error (E) is 41

Find out more at: brainly.com/question/10501147

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3 years ago
Brittany had 7 rolls of quarters and four extra quarters. She use the equation n = 7q + 4 to n, the number of quarter she had al
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She would use n-4=7q to find how many quarters in each roll.
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4 years ago
Ten engineering schools in the United States were surveyed. The sample contained 250 electrical engineers, 80 being women; 175 c
steposvetlana [31]

Answer:

There is a significant difference between the two proportions.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for difference between population proportions is:

CI=(\hat p_{1}-\hat p_{2})\pm z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})}{n_{1}}+\frac{\hat p_{2}(1-\hat p_{2})}{n_{2}}}

Compute the sample proportions as follows:

\hat p_{1}=\frac{80}{250}=0.32\\\\\hat p_{2}=\frac{40}{175}=0.23

The critical value of <em>z</em> for 90% confidence interval is:

z_{0.10/2}=z_{0.05}=1.645

Compute a 90% confidence interval for the difference between the proportions of women in these two fields of engineering as follows:

CI=(\hat p_{1}-\hat p_{2})\pm z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})}{n_{1}}+\frac{\hat p_{2}(1-\hat p_{2})}{n_{2}}}

     =(0.32-0.23)\pm 1.645\times\sqrt{\frac{0.32(1-0.32)}{250}+\frac{0.23(1-0.23)}{175}}\\\\=0.09\pm 0.0714\\\\=(0.0186, 0.1614)\\\\\approx (0.02, 0.16)

There will be no difference between the two proportions if the 90% confidence interval consists of 0.

But the 90% confidence interval does not consists of 0.

Thus, there is a significant difference between the two proportions.

4 0
3 years ago
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