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Allushta [10]
3 years ago
5

What is the value of x? x−15=8 in simplest form.

Mathematics
2 answers:
Bad White [126]3 years ago
7 0

Answer: x = 23

Step-by-step explanation:

first, move the constant to the right.

x = 8 + 15

then, simply calculate.

x = 23.

yanalaym [24]3 years ago
4 0

Answer:

x = 23

Step-by-step explanation:

Isolate x.

x - 15 = 8

x = 15 + 8

x = 23

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A bowl has the shape of a hemisphere whose diameter is 14 centimeters. If this bowl is filled with water, how many cubic centime
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Answer:

The cubic centimeters of water it will take to fill the bowl is 718.67 cm³

Step-by-step explanation:

Given;

diameter of the hemisphere, d = 14 cm

radius of the hemisphere, r = d/2 = 14/2  = 7 cm

The volume of the hemisphere is calculated as;

V = \frac{2}{3} \pi r^3\\\\V = \frac{2}{3} \times \frac{22}{7}   \times (7 \ cm)^3\\\\V = 718.67 \ cm^3

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3 years ago
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Calculus 2 Master needed, evaluate the indefinite integral of: <img src="https://tex.z-dn.net/?f=%5Cint%5C%28%20%28lnx%29%5E2%7D
viva [34]

Answer:

\int (\ln(x))^2dx=x(\ln(x)^2-2\ln(x)+2)+C

Step-by-step explanation:

So we have the indefinite integral:

\int (\ln(x))^2dx

This is the same thing as:

=\int 1\cdot (\ln(x))^2dx

So, let's do integration by parts.

Let u be (ln(x))². And let dv be (1)dx. Therefore:

u=(\ln(x))^2\\\text{Find du. Use the chain rule.}\\\frac{du}{dx}=2(\ln(x))\cdot\frac{1}{x}

Simplify:

du=\frac{2\ln(x)}{x}dx

And:

dv=(1)dx\\v=x

Therefore:

\int (\ln(x))^2dx=x\ln(x)^2-\int(x)(\frac{2\ln(x)}{x})dx

The x cancel:

=x\ln(x)^2-\int2\ln(x)dx

Move the 2 to the front:

=x\ln(x)^2-2\int\ln(x)dx

(I'm not exactly sure how you got what you got. Perhaps you differentiated incorrectly?)

Now, let's use integrations by parts again for the integral. Similarly, let's put a 1 in front:

=x\ln(x)^2-2\int 1\cdot\ln(x)dx

Let u be ln(x) and let dv be (1)dx. Thus:

u=\ln(x)\\du=\frac{1}{x}dx

And:

dv=(1)dx\\v=x

So:

=x\ln(x)^2-2(x\ln(x)-\int (x)\frac{1}{x}dx)

Simplify the integral:

=x\ln(x)^2-2(x\ln(x)-\int (1)dx)

Evaluate:

=x\ln(x)^2-2(x\ln(x)-x)

Now, we just have to simplify :)

Distribute the -2:

=x\ln(x)^2-2x\ln(x)+2x

And if preferred, we can factor out a x:

=x(\ln(x)^2-2\ln(x)+2)

And, of course, don't forget about the constant of integration!

=x(\ln(x)^2-2\ln(x)+2)+C

And we are done :)

8 0
3 years ago
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