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3 years ago

5

There are 20 students on the schools student council. A special homecoming dance committee is to be formed by randomly selecting

seven students from student council. How many possible committees can be formed?

1 answer:

babymother [125]3 years ago

3 0

You have to take 20/7 and you get a answer of <span>2.85 as a decimal. or a mixed number of 2 17/20</span>

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Answer the question in the photo please

Kisachek [45]

Answer:

Brian because if you do the math correctly it should be Brian

8 0

3 years ago

Read 2 more answers

What percentage is 142-58

Misha Larkins [42]

SOLUTION:

Step 1 :

In this question, we are meant to find what percent of 142 is 58.

Step 2 :

We make the assumption that 142 is 100 % since it is our output value.

Step 3:

We next represent the value we see with x.

Step 4 :

From step 2, it follows that 100 % = 142.

Step 5 :

In the same vein, x % = 58.

Step 6 :

This gives us a pair of simple equations:

$\begin{gathered} 100\text{ \% = 142 ---- equ 1} \\ x\text{ \% = 58 }\ldots\ldots\ldots\ldots\text{ equ 2} \end{gathered}$

Step 7 :

By simply dividing equation 1 by equation 2 and

taking note of the fact that the Left-Hand Side of both equations have the same unit ( % ), we have that :

$\frac{100\text{ \%}}{x\text{ \%}}\text{ = }\frac{142}{58}$

Step 8 :

Taking the inverse ( or reciprocal ) of both sides yields:

$\frac{x\text{ \%}}{100\text{ \%}}\text{ = }\frac{58}{142}$ $\begin{gathered} x\text{ = }\frac{58\text{ x 100}}{142} \\ \text{x = }\frac{5800}{142} \\ x\text{ = 40.85\%} \end{gathered}$

CONCLUSION:

Therefore, 58 is 40.85 % of 142.

4 0

2 years ago

Solve: 1. 1/6y− 1/2 =3− 1/2y 2. 4x+1/15 = 2x/10

kogti [31]

<u>Answer:</u>

<em>First Equation → </em><u><em>y = 21/4</em></u>

<em>Second Equation → </em><u><em>x = -1/57</em></u>

<u />

<u>Explanation:</u>

<em>solving equation #1</em>

<em></em>

step 1 - simplify

<em></em>

$\displaystyle\frac{1}{6}y - \displaystyle\frac{1}{2} = 3 - \displaystyle\frac{1}{2}y\\\\\displaystyle\frac{1}{6}* \displaystyle\frac{y}{1} - \displaystyle\frac{1}{2} = 3 - \displaystyle\frac{1}{2}* \displaystyle\frac{y}{1}\\\\\displaystyle\frac{y}{6} - \displaystyle\frac{1}{2} = 3 - \displaystyle\frac{y}{2}$

step 3 - multiply each side of the equation by six

$\displaystyle\frac{y}{6} - \displaystyle\frac{1}{2} = 3 - \displaystyle\frac{y}{2}\\\\\displaystyle\frac{y}{6} * \displaystyle\frac{6}{1}- \displaystyle\frac{1}{2} * \displaystyle\frac{6}{1}= \displaystyle\frac{3}{1} *\displaystyle\frac{6}{1} - \displaystyle\frac{y}{2}* \displaystyle\frac{6}{1}\\\\y - 3 = 18 - 3y$

step 4 - add three to both sides of the equation.

$y - 3 = 18 - 3y\\\\y-3+3=18+3-3y\\\\y = -3y+21$

step 5 - add three y to both sides of the equation.

$y = -3y+21\\\\y+3y = -3y+3y+21\\\\y+3y=21$

step 6 - simplify

$y+3y=21\\\\4y=21$

step 7 - divide both sides of the equation by four

$4y=21\\\\\displaystyle\frac{4y}{4} = \displaystyle\frac{21}{4}\\ \\y = \displaystyle\frac{21}{4}$

Therefore, the solution to the first given equation is <u><em>y = 21/4 </em></u><em>or y = 5.25.</em>

<u><em /></u>

<em>solving equation #2</em>

<em />

step 1 - simplify.

$4x + \displaystyle\frac{1}{15} = \displaystyle\frac{2x}{10} \\\\4x + \displaystyle\frac{1}{15} = 2*\displaystyle\frac{x}{10}\\\\4x+\displaystyle\frac{1}{15} = \displaystyle\frac{x}{5}$

step 2 - multiply each side of the equation by five.

$4x+\displaystyle\frac{1}{15} = \displaystyle\frac{x}{5}\\\\\displaystyle\frac{4x}{1}* \displaystyle\frac{5}{1} +\displaystyle\frac{1}{15} * \displaystyle\frac{5}{1} = \displaystyle\frac{x}{5}* \displaystyle\frac{5}{1} \\\\20x + \displaystyle\frac{1}{3} = x$

step 3 - subtract twenty x from each side of the equation.

$20x + \displaystyle\frac{1}{3} = x \\\\20x -20x+ \displaystyle\frac{1}{3} = x -20x\\\\\displaystyle\frac{1}{3} = -19x$

step 4 - divide each side of the equation by negative nineteen.

$\displaystyle\frac{1}{3} = -19x\\\\\displaystyle\frac{\displaystyle\frac{1}{3} }{-19} = \displaystyle\frac{-19x}{-19} \\\\-\displaystyle\frac{1}{57} = x$

step 5 - switch

$-\displaystyle\frac{1}{57} =x\\\\x = -\displaystyle\frac{1}{57}$

Therefore, the solution to the second equation is <em><u>x = -1/57.</u></em>

5 0

3 years ago

Write an expression that represents the statement " the product of 6 and the sum of 3 times a number n and 5"

kramer

6(3x + 5 )

hope that helps

5 0

3 years ago

Use the quadratic model y=-4x^2-3x+4 to predict y if x equals 5.

Vitek1552 [10]

Answer:

y = - 111

Step-by-step explanation:

Substitute x = 5 into the quadratic for y

y = - 4(5)² - 3(5) + 4 = - 100 - 15 + 4 = - 111

4 0

3 years ago