The equation of a line that passes through the point (x1,y1) and has a slope of m is y-y1=m(x-x1)
given
(6,-3)
(x1,y1)
and slope is 1/2
y-(-3)=1/2(x-6)
y+3=1/2(x-6)
that is point slope
I believe 3/15 would be fedoras
4:20 = 1:5
1:5 = 3:15
7^2 - 3(4-2)^0 - 2(7+3) + 3^2
= 49 - 3 - 20 + 9
= 35
hope it helps
P.S
any number to the 0 power is always equal 1
None of them make it an integer because none make it a whole number
Answer:
(3x-4)(x-5)
Step-by-step explanation:
This is in the form
ax²+bx+c.
To factor this, we find factors of a·c that sum to b; this means factors of 3(20) = 60 that sum to -19:
60 = 1(60) or -1(-60); 2(30) or -2(-30); 3(20) or -3(-20); 4(15) or -4(-15); 5(12) or -5(-12); 6(10) or -6(-10). The only of these that sum to -19 are -4 and -15. This means we will split up -19x into -4x and -15x:
3x²-4x-15x+20
Next we group the first two terms and the last two terms:
(3x²-4x)+(-15x+20)
Factor out the GCF of each group. For the first group, this is x:
x(3x-4)
For the second group, this is -5:
-5(3x-4)
The common factor for these two groups is (3x-4):
(3x-4)(x-5)
