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Travka [436]
3 years ago
15

A bowl contains 15 granola bars and 10 fruit bars.

Mathematics
1 answer:
horsena [70]3 years ago
5 0
Granola bars to fruit bars....
15 / 10 reduces to 3/2 in simplest form......so its 3/2, or 3:2, or 3 to 2
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Ingrid hit a golf ball. The height of the ball (in meters above the ground) t seconds after being hit is modeled by h(t)=-5t^2+3
valina [46]

Answer:

1) h(t) = -5(t-3)^2

2) The ball reaches the highest point at 3 seconds.

Step-by-step explanation:

OK. So for this question, I recommend to rewite using vertex form since the answer is given in a more concise manner than using factored.  

First Step:

h(t) = -5t^2+30t

= -5(t^2-6t)

= -5(t^2-6t+9)+45

= -5(t-3)^2+45

Second Step:

The vertex form reveals the vertex to be at (3, 45).

Therefore, the ball reaches the highest point at 3 seconds.

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3 years ago
Write the two-column proof from start to finish.
abruzzese [7]

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Step-by-step explanation:

3 0
4 years ago
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Aleks [24]

Answer:

n = -8

Step-by-step explanation:

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5-5+n/8=4-5

n/8 = -1

Multiply each side by 8

n/8 * 8 = -1 *8

n = -8

5 0
3 years ago
Mike and Teegan each measured the volume of the 16-ounce bottle three times. They recorded their measurements as shown.
bazaltina [42]

Answer:

Mike's measurement are more precise and more accurate

Step-by-step:

Edge2020

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4 years ago
Our class has 50 students. Assuming that no students are born on leap days (February29), what is the probability that no two stu
madreJ [45]

Answer:  a) \dfrac{799}{31250}  b) \dfrac{30451}{31250}

Step-by-step explanation:

Since we have given that

Number of days in a year = 365

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Probability that no two students share the same birthday. It means each student has different birthday.  

Probability(no two students share the same birthday)=\dfrac{365-1}{365}\times \dfrac{365-2}{365}........\times \dfrac{365-50}{365}

Probability(no two students share the same birthday)=\dfrac{^{365}P_{50}}{365^{50}}

Probability(no two students share the same birthday)=\dfrac{799}{31250}\approx 0.025568

Probability that at least one of the students has the same birthday as another student in the class is given by

1-P(\text{no student share the same birthday})\\\\=1-\dfrac{799}{31250}\\\\=\dfrac{30451}{31250}=0.974432

5 0
4 years ago
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