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Anit [1.1K]
4 years ago
5

I need help with this answer please and thank you...​

Mathematics
2 answers:
belka [17]4 years ago
7 0
11) patty 12) 4 and 1/4 pounds
Genrish500 [490]4 years ago
7 0

Step-by-step explanation:

11.)

To figure this out, simply just take the fraction and multiply it by the number of days.

5/6 × 5 = 25/6 = 4.2 mi.

3/4 × 6 = 9/2 = 4.5 mi.

Keisha will run a greater distance than Patty.

12.)

To figure this out, divide the 5 pounds of dough into 5 parts. This will give us a pound each. (1/5 = 1 pound)

So if the baker uses 4/5 of the dough, that will leave 1/5. This means the baker will have 1 pound of dough left over.

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Given the linear equation r=-2.5 t and t can only be a negative number, what quandrant will the r coordinate be located?
Citrus2011 [14]

Answer:

quadrant 4 i think

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Use the graph to determine the domain and range of the relation, and whether the relation is a function
ohaa [14]
The answer is C. The domain is all points between -8 and 8 since it keeps waving back and forth. The range is all real numbers the graph continues on forever. And it is not a function because it does not pass the vertical line test
6 0
3 years ago
How am i supposed to make a function? Number 15
Greeley [361]

Part A

<h3>Answer: T(n) = 58n+1800</h3>

-------------

Work Shown:

1800 = initial cost or starting cost

58*1 = 58 = cost for one person

58*2 = 116 = cost for two people

58*n = cost for n people

58n+1800 = total cost

58n+1800 = T(n)

T(n) = 58n+1800

======================================

Part B

<h3>Answer: D(T) = 0.85T</h3>

-------------

Work Shown:

T = total bill

15% discount means you still pay 85% of the bill (85%+15% = 100%)

D = discounted cost

D = 85% of T

D = 0.85*T

======================================

Part C

<h3>Answer: D(T(n)) = 49.3n + 1530</h3><h3>See attached image below for the table.</h3>

-------------

Work Shown:

We combine parts A and B.

T(n) = 58n+1800 from part A

D(T) = 0.85*T from part B

D(T(n)) = 0.85*( T(n) )

D(T(n)) = 0.85*( 58n+1800 ) ... plug in T(n) = 58n+1800

D(T(n)) = 0.85*( 58n+1800 )

D(T(n)) = 0.85*(58n)+0.85*(1800) ... distribute

D(T(n)) = 49.3n + 1530

If we plugged in n = 0, then,

D(T(n)) = 49.3n + 1530

D(T(0)) = 49.3*0 + 1530

D(T(0)) = 1530

Or we could plug n = 0 into T(n) to get T(0) = 1800

Then plug T = 1800 into D(T) = 0.85*T to get D(1800) = 1530

Either way you'll get the same answer.

Repeat this (using either method) for n = 50, 100, 150, 200 and you'll get the table of values you see below in the attached image.

======================================

Part D

The D( T(n) ) function allows us to find the discounted cost D for any number n of people that show up.

The input is n, where n is some positive integer less than or equal to 200 (because this is the reception hall's max capacity).

The output is the final discounted cost.

Example: n = 50 is one input which leads to its corresponding output of D( T(n) ) = 3995 as the table shows. So 50 people would have a discounted total cost of $3,995.

5 0
4 years ago
There are 450 students at a school. If each classroom holds 30 students , how many classrooms are needed at school?
Sati [7]

Answer:

15 classrooms

Step-by-step explanation:

3 0
4 years ago
Is this right. Please help me
My name is Ann [436]

Answer:

ye that is the correct answer

3 0
3 years ago
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