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ser-zykov [4K]
3 years ago
9

A Windows user has been successfully saving documents to the file server all morning. However, the latest attempt resulted in th

e following message, "Could not find this item. Verify the location of '\\FileServer\Docs' and try again."
Which of the following is the most likely cause for this message?

a. The user's PC is out of local hard disk space.
b. The file server could not contact directory services.
c. The share to the file server is disconnected.
d. The user signed out of directory services
Computers and Technology
2 answers:
Natalka [10]3 years ago
8 0

Answer:

c. The share to the file server is disconnected.

Explanation:

Sharing a file to the file server is the same as saving the document to the file server as the most important function of file server is storage. Therefore if one is getting an error message of not being able to find the saved file and to verify the location of '\\FileServer\Docs', it means that the saved files are no longer available anywhere on the server and even in the computer of the user.

Anna [14]3 years ago
8 0

Answer:

c. The share to the file server is disconnected.

Explanation:

A file server is responsible for storing and retrieving of files used by all other computers that are connected to it via a network. The file sharing protocol that are commonly use to access file servers on a local area network(LAN) could be Server Message Block or Common Internet File System.

The messages implies that the network access protocol to the file server has been disconnected, hence the reason the file server could not be accessed.

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Write a statement that terminates the current loop when the value of the int variables x. and y.are equal
lakkis [162]
To <span>rite a statement that terminates the current loop when the value of the int variables x. and y.are equal please check below:
</span>
if (x == y) break; // exit loop 

I hope the answer will help you. Thank you. 

6 0
3 years ago
. List four different ways automation can be used in testing?
hichkok12 [17]

Answer:

Automation testing can be used for:

<u>Input-output test :</u> If the main function of your software is to transform input data into output data you can configure a new test by providing a new input/output pair, then the test will check to see if the output matches with the expected values.

<u>Unit test :</u> This test is a script to check the return values of a specific code by initializing it and calling his methods. This is a part of a test-driven development process.

<u>Integration test :</u> This test is a code level script that does a complete check process involving multiple objects. For example, you might make a test for “buy a product” which checks to see if the database is updated, if the data is correct of the person is correct, and if the person placing the order gets the right confirmation email.

<u>Smoke Tests:</u> This test is executed immediately after implementation on production to ensure that the application is still functioning.

6 0
3 years ago
G The method of mapping where each memory locationis mapped to exactly one location in the cache is
Otrada [13]

Answer:

Direct Mapped Cache

Explanation:

Given that a Direct Mapped Cache is a form of mapping whereby each main memory address is mapped into precisely one cache block.

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4 0
3 years ago
Columns can be added to a page in the page layout tab in the blank grouping
ZanzabumX [31]

Answer:

Page Setup Grouping.

Explanation:

In Microsoft Word, Columns break up the page into, at max, 13 columns, and at minumum, 2. The way you go about doing this is

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3 0
4 years ago
Read 2 more answers
Input 10 integers and display the following:
LekaFEV [45]

Answer:

// code in C++

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

   // variables

   int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;

   int largest=INT_MIN;

   int smallest=INT_MAX;

   int n;

   cout<<"Enter 10 Integers:";

   // read 10 Integers

   for(int a=0;a<10;a++)

   {

       cin>>n;

       // find largest

       if(n>largest)

       largest=n;

       // find smallest

       if(n<smallest)

       smallest=n;

       // if input is even

       if(n%2==0)

       {  

           // sum of even

           sum_even+=n;

           // even count

           eve_count++;

       }

       else

       {

           // sum of odd    

          sum_odd+=n;

          // odd count

          odd_count++;

       }

   }

   

   // print sum of even

   cout<<"Sum of all even numbers is: "<<sum_even<<endl;

   // print sum of odd

   cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;

   // print largest

   cout<<"largest Integer is: "<<largest<<endl;

   // print smallest

   cout<<"smallest Integer is: "<<smallest<<endl;

   // print even count

   cout<<"count of even number is: "<<eve_count<<endl;

   // print odd cout

   cout<<"count of odd number is: "<<odd_count<<endl;

return 0;

}

Explanation:

Read an integer from user.If the input is greater that largest then update the  largest.If the input is smaller than smallest then update the smallest.Then check  if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.

Output:

Enter 10 Integers:1 3 4  2 10 11 12 44 5 20                                                                                

Sum of all even numbers is: 92                                                                                            

Sum of all odd numbers is: 20                                                                                              

largest Integer is: 44                                                                                                    

smallest Integer is: 1                                                                                                    

count of even number is: 6                                                                                                

count of odd number is: 4

3 0
4 years ago
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