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ser-zykov [4K]
3 years ago
9

A Windows user has been successfully saving documents to the file server all morning. However, the latest attempt resulted in th

e following message, "Could not find this item. Verify the location of '\\FileServer\Docs' and try again."
Which of the following is the most likely cause for this message?

a. The user's PC is out of local hard disk space.
b. The file server could not contact directory services.
c. The share to the file server is disconnected.
d. The user signed out of directory services
Computers and Technology
2 answers:
Natalka [10]3 years ago
8 0

Answer:

c. The share to the file server is disconnected.

Explanation:

Sharing a file to the file server is the same as saving the document to the file server as the most important function of file server is storage. Therefore if one is getting an error message of not being able to find the saved file and to verify the location of '\\FileServer\Docs', it means that the saved files are no longer available anywhere on the server and even in the computer of the user.

Anna [14]3 years ago
8 0

Answer:

c. The share to the file server is disconnected.

Explanation:

A file server is responsible for storing and retrieving of files used by all other computers that are connected to it via a network. The file sharing protocol that are commonly use to access file servers on a local area network(LAN) could be Server Message Block or Common Internet File System.

The messages implies that the network access protocol to the file server has been disconnected, hence the reason the file server could not be accessed.

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In java write a program:A contact list is a place where you can store a specific contact with other associated information such
BigorU [14]

Answer:

import java.util.Scanner;

public class ContactInformation

{

public static String GetPhoneNumber(String[] nameVec, String[] phoneNumberVec, String contactName, int arraySize)  

{  

for(int i=0;i<arraySize;i++)

{

if(nameVec[i].equals(contactName))  

return phoneNumberVec[i];

}  

return "Contact doesn't exists!";

}

public static void main(String[] args)

{

int records;

Scanner sc = new Scanner(System.in);

System.out.print("Enter the size of contact List :");

records=sc.nextInt();

String[] contactNameList=new String[records];

String[] phoneNumberList=new String[records];

String contactName;

System.out.println("Enter the contact name and phone number :");

for(int i=0;i<contactNameList.length;i++)

{  

contactNameList[i]=sc.next();  

phoneNumberList[i]=sc.next();  

}  

System.out.println("Enter the name of the contact to be searched :");  

contactName=sc.next();

System.out.println(GetPhoneNumber(contactNameList,phoneNumberList,contactName,records));  

}  

}

Explanation:

In the following the function defined above for getting the contact

number on the basis of contact number provided we are checking the contact name list if we are able to find the contact name and if we did we return the contact number on the same index from the contact number list

which we found in the contact name list.

4 0
3 years ago
What should you do when you encounter an active directory domain controller for the domain could not be contacted?
Nostrana [21]

Answer:

Issue the Dcdiag on all domain controller servers.

Explanation:

Active directory is a database that holds information of client's authentication for service access in a server. Domain controllers in servers holds these active directories, to replicate client's credentials for quick response to access to the server.

When a server domain can not contact the active directory domain controller, the Dcdiag command is issued on the server to check for connectivity issue to the DNS, AD replication, SYSVOL replication etc.

8 0
4 years ago
In a __________, you are trying to find what others have prepared. With __________, you are trying to discover new patterns that
AveGali [126]

Answer:

<u>query,</u> <u>data mining </u>

Explanation:

A query can be explained as another term for question.

If one needs additional information from some other person, he might have ask to him. Queries are used for the retrieval of the information.

In other words, one tries to find what have been prepared by others.

Data mining can be explained as the process that allows to sort through a large set of data for the identification of patterns.

In this process of data mining, one tries to find out the new patterns that may not be known at all.

3 0
4 years ago
Who wants to join my zoom after school 23456+4567
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3 years ago
Write a class called Course that represents a course taken at a school. Represent each student using the modified Student class
Vinvika [58]

Answer:

The code is given below with its appropriate output

Explanation:

//Student.java

import java.io.BufferedReader;

import java.io.FileReader;

import java.io.IOException;

import java.util.Scanner;

public class Student {

public String firstName;

public String lastName;

public float[] marks;

Scanner scanner = new Scanner(System.in);

public Student(String firstName, String lastName) {

this.firstName = firstName;

this.lastName = lastName;

}

public void getdetail() {

System.out.println("enter only five marks");

marks = new float[5];

int count = 0;

for (int i = 0; i < 5; i++) {

float mark = 0;

++count;

if (count <= 5) {

System.out.println("enter score " + count);

mark = scanner.nextFloat();

if (mark >= 0.0 && mark <= 100.0)

marks[i] = mark;

else {

System.out.println("you entered mark is invalid");

marks[i] = 0;

}

} else

System.out.println(" maximum is five only");

}

}

public void tostring() {

System.out.println("firstname :" + "\t" + firstName + "\t" + "lastname :"

+ "\t" + lastName + "\n" + "the marks are");

int count = 0;

for (float mark : marks) {

count++;

System.out.println("the mark of " + count + " is " + mark);

}

}

public void Averagecal() {

float sum = 0.0f;

for (float mark : marks) {

sum = sum + mark;

}

float avg = sum / 5;

System.out.println("average of a student is " + avg);

}

}

//Course.java

import java.io.*;

import java.io.BufferedReader;

import java.io.FileReader;

import java.io.IOException;

import java.util.Scanner;

public class Course {

public String courseName;

public int number;

Student[] students;

Scanner scanner = new Scanner(System.in);

public Course(String courseName) {

this.courseName = courseName;

}

public void addStudents() {

System.out

.println("how many no of students you want to add for this particular course");

int count = scanner.nextInt();

students = new Student[count];

for (int i = 0; i < count; i++) {

System.out.println("enter the first name");

String fname = scanner.next();

System.out.println("enter the last name");

String lname = scanner.next();

Student s = new Student(fname, lname);

s.getdetail();

s.tostring();

s.Averagecal();

students[i] = s;

}

}

public void roll() {

int count = 0;

for (Student stud : students) {

count++;

}

System.out.println("the no of students in this " + courseName

+ " course is " + count);

}

}

//Driver.java

import java.io.BufferedReader;

import java.io.FileReader;

import java.io.IOException;

import java.util.Scanner;

public class Driver {

public static void main(String[] args) {

Course course = new Course("java");

course.addStudents();

course.roll();

}

}

<u>output: </u>

C:\Users\Daniel\Desktop\New folder>javac Student.java

C:\Users\Danie;\Desktop\New folder>javac Course.java

C:\Users\Daniel\Desktop\New folder>javac Driver.java

C:\Users\Daniel\Desktop\New folder>java Driver

how many no of students you want to add for this particular course ?

1

enter the first name

john

enter the last name

rich

enter only five marks

enter score 1

89

enter score 2

91

enter score 3

85

enter score 4

78

enter score 5

96

firstname : john lastname : rich

the marks are

the mark of 1 is 89.0

the mark of 2 is 91.0

the mark of 3 is 85.0

the mark of 4 is 78.0

the mark of 5 is 96.0

average of a student is 87.8

the no of students in this java course is 1

C:\Users\Ravi\Desktop\New folder>

3 0
3 years ago
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