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ser-zykov [4K]
3 years ago
9

A Windows user has been successfully saving documents to the file server all morning. However, the latest attempt resulted in th

e following message, "Could not find this item. Verify the location of '\\FileServer\Docs' and try again."
Which of the following is the most likely cause for this message?

a. The user's PC is out of local hard disk space.
b. The file server could not contact directory services.
c. The share to the file server is disconnected.
d. The user signed out of directory services
Computers and Technology
2 answers:
Natalka [10]3 years ago
8 0

Answer:

c. The share to the file server is disconnected.

Explanation:

Sharing a file to the file server is the same as saving the document to the file server as the most important function of file server is storage. Therefore if one is getting an error message of not being able to find the saved file and to verify the location of '\\FileServer\Docs', it means that the saved files are no longer available anywhere on the server and even in the computer of the user.

Anna [14]3 years ago
8 0

Answer:

c. The share to the file server is disconnected.

Explanation:

A file server is responsible for storing and retrieving of files used by all other computers that are connected to it via a network. The file sharing protocol that are commonly use to access file servers on a local area network(LAN) could be Server Message Block or Common Internet File System.

The messages implies that the network access protocol to the file server has been disconnected, hence the reason the file server could not be accessed.

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With a presentation open, you can hover your mouse pointer over a design theme on the Design tab, and PowerPoint will display th
algol [13]

Answer: Live preview

Explanation:

The live preview feature enables to display the current slide with the design theme formatting applied with the mouse pointer. This feature is also available in digital cameras where the screen can be used as viewfinder.

6 0
3 years ago
1. Build and test D-type Flip-Flop using a built-in SR flip-flop.
GaryK [48]

Answer:

The attached files contain the realization of a D flip-flop from an RS flip-flop. It also contains the truth tables for both kinds of flip-flops

Explanation:

An SR flip flop is like a light switch. Set turns it 'on' and reset turns it 'off'

A D type flip-flop is a clocked flip-flop which has two stable states. A D type flip-flop operates with a delay in input by one clock cycle.

D type flip-flops are easily constructed from an SR flip-flop by simply connecting an inverter between the S and the R inputs so that the input to the inverter is connected to the S input and the output of the inverter is connected to the R input.

8 0
3 years ago
Which one of the following word processing features saves you the most time when keying a document?
drek231 [11]
C) find and replace which finds the words you want to replace in a document and replaces them to whatever you specify
3 0
3 years ago
Find the root using bisection method with initials 1 and 2 for function 0.005(e^(2x))cos(x) in matlab and error 1e-10?
frutty [35]

Answer:

The root is:

c=1.5708

Explanation:

Use this script in Matlab:

-------------------------------------------------------------------------------------

function  [c, err, yc] = bisect (f, a, b, delta)

% f the function introduce as n anonymous function

%       - a y b are the initial and the final value respectively

%       - delta is the tolerance or error.

%           - c is the root

%       - yc = f(c)

%        - err is the stimated error for  c

ya = feval(f, a);

yb = feval(f, b);

if  ya*yb > 0, return, end

max1 = 1 + round((log(b-a) - log(delta)) / log(2));

for  k = 1:max1

c = (a + b) / 2;

yc = feval(f, c);

if  yc == 0

 a = c;

 b = c;

elseif  yb*yc > 0

 b = c;

 yb = yc;

else

 a = c;

 ya = yc;

end

if  b-a < delta, break, end

end

c = (a + b) / 2;

err = abs(b - a);

yc = feval(f, c);

-------------------------------------------------------------------------------------

Enter the function in matlab like this:

f= @(x) 0.005*(exp(2*x)*cos(x))

You should get this result:

f =

 function_handle with value:

   @(x)0.005*(exp(2*x)*cos(x))

Now run the code like this:

[c, err, yc] = bisect (f, 1, 2, 1e-10)

You should get this result:

c =

   1.5708

err =

  5.8208e-11

yc =

 -3.0708e-12

In addition, you can use the plot function to verify your results:

fplot(f,[1,2])

grid on

5 0
3 years ago
This exercise asks you to write a program that tests some of the built-in subroutines for working with Strings. The program shou
klasskru [66]

Answer:

Java.

Explanation:

// Get user input

System.out.print("Please enter your first name and last name separated by a space: ");

userInput = TextIO.getln();

// Find index of space character

int spaceIndex = userInput.indexOf(' ');

// Extract first and last name using space character index

// I have used length() method to get length of string userInput.

String firstName = userInput.substring(0, spaceIndex-1);

String lastName = userInput.substring(spaceIndex+1, userInput.length()-1);

// Print the required statements

System.out.print("Your first Name is %s, which has %d characters%n", firstName, firstName.length());

System.out.print("Your last Name is %s, which has %d characters%n", lastName, lastName.length());

// I have used space character Index to get the Initial of last name

System.out.print("Your initials are %s%s", firstName.substring(0,0), lastName.substring(spaceIndex+1, spaceIndex+1));

5 0
3 years ago
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