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2 years ago

Which statement comparing |−12| and |8| is true?

Mathematics

2 answers:

serg [7]2 years ago

7 0

Answer:

|-12| > |8|

Step-by-step explanation:

In this question we have two absolute values which are

Absolute value is always positive. That is absolute value of negative number is the positive number and absolute value

So the correct andswer is

|-12| > |8|

Alinara [238K]2 years ago

5 0

They are both positive. Also, they're both rational, even, natural, integer, multiples of 4 .

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A box contains eight cards labeled P, Q, R, S, T, U, V, and W. One card will be randomly chosen.

Varvara68 [4.7K]

Answer:

7/8

Step-by-step explanation:

Probability= (Cards having letter Q to W)/(All cards) = 7/8

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2 years ago

Prove that the two circles shown below are similar.

s344n2d4d5 [400]

The circles B and D are similar since the radius of the former is as twice as the radius of the latter.

<h3>Are the two circles shown in the figure similar?</h3>

By geometry we know that circles are defined by only one characteristic: radius. If two circles are similar, then the radii must be <em>different</em>. After a quick look at the figure, we conclude that the radii are $r_{B} = 4$ and $r_{D} = 2$ . Hence, the circles B and D are similar since the radius of the former is as twice as the radius of the latter.

To learn more on similarity: brainly.com/question/12670209

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1 year ago

Select the correct symbol to compare the expressions below.

oksano4ka [1.4K]

Answer:

Step-by-step explanation:

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2 years ago

Write and solve an equation. Tommy has 5 more toy cars than Billy does. If Tommy has 12 toy cars, how many cars, c, does Billy h

8090 [49]

12-5=7 so billy has 7 toy cars

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2 years ago

Simplify and answer the boxes.

s2008m [1.1K]

Answer:

$\huge\boxed{\dfrac{x^2+9^2}{x-3y}+\dfrac{6xy}{3y-x}=x-3y}$

Step-by-step explanation:

Domain:

$x-3y\neq0\Rightarrow x\neq3y$

$\dfrac{x^2+9y^2}{x-3y}+\dfrac{6xy}{3y-x}=\dfrac{x^2+9y^2}{x-3y}+\dfrac{6xy}{-(x-3y)}\\\\=\dfrac{x^2+9y^2}{x-3y}-\dfrac{6xy}{x-3y}=\dfrac{x^2+9y^2-6xy}{x-3y}\\\\=\dfrac{x^2-2(x)(3y)+(3y)^2}{3y-x}=\dfrac{(x-3y)^2}{3y-x}\\\\=\dfrac{\bigg[-1(3y-x)\bigg]^2}{3y-x}=\dfrac{(-1)^2(3y-x)^2}{3y-x}\\\\=\dfrac{1(x-3y)(x-3y)}{x-3y}=x-3y$

Used:

The distributive property: a(b + c) = ab + ac

(a - b)² = a² - 2ab + b²

6 0

2 years ago

Which statement comparing ​ |−12| ​ and ​ |8| ​ is true?

Which statement comparing |−12| and |8| is true?