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kow [346]
3 years ago
13

Solve the equation (0°≤A≤360°)a) √3sinA-cosA=√2​

Mathematics
1 answer:
Blizzard [7]3 years ago
6 0

Step-by-step explanation:

√3sinA-cosA=√2

dividing both side by (√3²-1²=2 we get)

√3/2 sinA-1/2.cos A=√2/2

cos 30sinA-sin30cosA=√2/(√2×√2)

sinAcos30-cosAsin30=1/√2

sin(A-30)=sin45,sin(180-45)

therefore

A-30=45,135

A=45+30=75 or A=135+30=165

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Step-by-step explanation:

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3 years ago
What is the sum of the arithmetic sequence 3, 9, 15..., if there are 36 terms?
EastWind [94]
We know that
the formula of the <span>the sum of the arithmetic sequence is
Sum=n*(a1+an)/2

n=36
a1=3
a36=?

find a36
an=a1+(n-1)*d

for n=2   a2=9
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so
for n=36
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</span>Sum=n*(a1+an)/2-----> 36*[3+213]/2----> 3888

the answer is
3888
8 0
4 years ago
Read 2 more answers
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