Question

If one card is randomly chosen from a standard deck, what is the probability that a 6 is chosen, GIVEN THAT A DIAMOND WAS CHOSEN?
A. 4/13
B. 1/52
C. 1/13
D. 1/4

If two cards are randomly chosen from a standard deck, what is the probability that a 6 is chosen, replaced, and another 6 is chosen?
A. 16/2652
B. 16/2704
C. 36/2704
D. 1/16

Answer 1

P(A|B) = P(A)*P(B) - P(A∩B)

Here, we have:

P(a 6 is chosen, given that a diamond was already chosen) = (1/4)(1/4)-(1/52) = 0.043