Answer:
Summation of the non variable Expression within the quality sign
1/2 + 1-2x= -13/2
3/2-2x= -13/2
Step-by-step explanation:
1/2-1/3(6x-3)=-13/2
First step
Using the distributive property to simply
1/2-(6x/3)+(3/3)=-13/2
1/2 -2x +1 = -13/2
Second step
Summation of the non variable Expression within the quality sign
1/2 + 1-2x= -13/2
3/2-2x= -13/2
Third step
Isolating the variable Expression by using the addition property of equality
-2x = -13/2 - 3/2
-2x = -16/2
Fourth step
Isolating the variable by using the division property of equality
-2x = -16/2
X = -16/2 * -1/2
X = -16/-4
X= 4
Question 21
Let's complete the square
y = 3x^2 + 6x + 5
y-5 = 3x^2 + 6x
y - 5 = 3(x^2 + 2x)
y - 5 = 3(x^2 + 2x + 1 - 1)
y - 5 = 3(x^2+2x+1) - 3
y - 5 = 3(x+1)^2 - 3
y = 3(x+1)^2 - 3 + 5
y = 3(x+1)^2 + 2
Answer: Choice D
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Question 22
Through trial and error you should find that choice D is the answer
Basically you plug in each of the given answer choices and see which results in a true statement.
For instance, with choice A we have
y < -4(x+1)^2 - 3
-7 < -4(0+1)^2 - 3
-7 < -7
which is false, so we eliminate choice A
Choice D is the answer because
y < -4(x+1)^2 - 3
-9 < -4(-2+1)^2 - 3
-9 < -7
which is true since -9 is to the left of -7 on the number line.
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Question 25
Answer: Choice B
Explanation:
The quantity (x-4)^2 is always positive regardless of what you pick for x. This is because we are squaring the (x-4). Squaring a negative leads to a positive. Eg: (-4)^2 = 16
Adding on a positive to (x-4)^2 makes the result even more positive. Therefore (x-4)^2 + 1 > 0 is true for any real number x.
Visually this means all solutions of y > (x-4)^2 + 1 reside in quadrants 1 and 2, which are above the x axis.
Answer:28.2753
Step-by-step explanation:
Answer:
Test statistic = -2.25
P-value = 0.0199
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 450 gram
Sample mean, 
= 441 grams
Sample size, n = 16
Alpha, α = 0.05
Sample variance = 256
First, we design the null and the alternate hypothesis
We use one-tailed t test to perform this hypothesis.
Formula:
Putting all the values, we have
Now,
Degree of freedom =
We can calculate the p-value from the table as:
P-value = 0.0199
Conclusion:
Since the p-value is smaller than the significance level we fail to accept the null hypothesis and reject it.
Thus, there is enough evidence to support the claim that the machine is under filling the bags .
