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trapecia [35]
3 years ago
11

Find the equation of the line tangent to the function at the given point f(x)=5x^2 at x=10

Mathematics
1 answer:
Svet_ta [14]3 years ago
8 0

f(x) = 5x²

f(10) = 5(10)²  = 5(100)  = 500

f'(x) = 10x

f'(10) = 10(10)   = 100  

Now, find the line that passes through (10, 500) and has a slope of 100

y - y₁ = m(x - x₁)

y - 500 = 100(x - 10)

y - 500 = 100x - 1000

        y = 100x - 500

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Answer:

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But before we add them, let's simplify them.

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Now to find the area, we use the formula:

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A = BH · 1/2

Where 'B' represents the base, 'H' stands for the height, and 1/2 means that you divide the product of the base and height by 2.

<u><em>What we know:</em></u>

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Plug in the values into our formula:-

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2 years ago
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Answer:

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8 0
3 years ago
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<em>Hi there!</em>

<em>~</em>

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