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3 years ago

PLEASE HELP! 30 POINTS for RIGHT answer!

Mathematics

1 answer:

yulyashka [42]3 years ago

5 0

gg easy

we want to cancel 1 term

first, get them into form am+bn=c where a, b, and c are constants

m-2n=2 is good

m+n=2(n-3) is m+n=2n-6 which is m-n=-6

compare constants

m's have 1 and 1

n's have -2 and -1

let's cancel m's

a. multiply 1st equation by -1

-m+2n=-2

add to 2nd equation

-m+2n=-2

0m+n=-8

n=-8

sub back

m-n=-6

m-(-8)=-6

m+8=-6

m=-14

b. to check

m=-14 and n=-8

m-2n=2

-14-2(-8)=2

-14+16=2

2=2 yep

m-n=-6

-14-(-8)=-6

-14+8=-6

-6=-6 yep

so m=-14 and n=-8 is the solution

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What is the quotient оf (x^3 + 3x^2– 4x– 12)-(х^2 + 5х+6)?

DIA [1.3K]

Answer:

The quotient is (x-2)

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Micah was asked to add the following expressions: 3x2−x−9x2+3x+2+−2x2+2x+5x2+3x+2 First, he combined like terms in the numerator

shtirl [24]

Micah was asked to add the following expressions:

$\frac{3x^2-x-9}{x^2+3x+2} + \frac{-2x^2+2x+5}{x^2+3x+2}$

First, he combined like terms in the numerator and kept the common denominator

First step is correct. He added the like terms in the numerator, because the denominators are same.

$3x^2 -x -9 -2x^2+2x+5becomes x^2 +x -4$

So he got , $\frac{x^2+x-4}{x^2+3x+2}$

In the next step, he cannot cancel out x^2 from the top and bottom . Because x-4 and 3x+2 are added with x^2

If we have x^2 is multiplied with other terms at the top and bottom , then we can cancel out x^2.

So Micah added the expression incorrectly. Final answer is not correct.

5 0

3 years ago

Help me plssss NO LINKS PLSSSSSSS

Tamiku [17]

Answer:

perimeter- 36 in.

area- 77 $in^2$

Step-by-step explanation:

to find the perimeter you add all of the sides, so

7 + 7 + 11 + 11 = 36

*** the opposite side of the 7 is also 7, same with the 11 :)

to find the area for a rectangle, you use the formula A=b*h

so, the base(b)=7 and the height(h)= 11

therefore, 7 * 11 = 77

I hope this helps!! :) if it does, brainliest?? :)

3 0

2 years ago

What is 2+2 pls help

Alexandra [31]

Answer:

Step-by-step explanation:

2 + 2 += 4

This can be solved by addition.

7 0

2 years ago

What are the next 3 numbers in this pattern of integers -2, -1, -1, 0, -1, 1, -2

sashaice [31]

Answer:

The next 3 numbers to the given pattern of integers is -2,-1,-1,0,-1,1,-2 are 3,-5,8

Step-by-step explanation:

Given pattern of integers is -2,-1,-1,0,-1,1,-2

To find their next 3 numbers of the given pattern :

Let $a_{1}=-2$

$a_{2}=-1$

$a_{3}=a_{1}-a_{2}$

$=-2-(-1)$

$=-2+1$

Therefore $a_{3}=-1$

$a_{4}=a_{2}-a_{3}$

$=-1-(-1)$

$=-1+1$

Therefore $a_{4}=0$

Similarly we have $a_{5}=-1$ , $a_{6}=1$ , $a_{7}=-2$

The general form to the given pattern is

$a_{n}=a_{n-2}+a_{n-1}$ for $n={\{1,2,3,4,5,6,7,8,9,10}\}$

Therefore to find the $a_{8},a_{9},a_{10}$

Put n=8 in $a_{n}=a_{n-2}-a_{n-1}$

$a_{8}=a_{8-2}-a_{8-1}$

$=a_{6}-a_{7}$

$=1-(-2)$

$a_{8}=3$

Put n=9 in $a_{n}=a_{n-2}-a_{n-1}$

$a_{9}=a_{9-2}-a_{9-1}$

$=a_{7}-a_{8}$

$=-2-(3)$

$a_{9}=-5$

Put n=10 in $a_{n}=a_{n-2}-a_{n-1}$

$a_{10}=a_{10-2}-a_{10-1}$

$=a_{8}-a_{9}$

$=3-(-5)$

$a_{10}=8$

Therefore the next 3 numbers are 3,-5,8

4 0

3 years ago