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diamong [38]
3 years ago
13

Tom rolls 2 fair dice and adds the results from each.

Mathematics
1 answer:
Delicious77 [7]3 years ago
5 0

Answer:

\dfrac{1}{12}

Step-by-step explanation:

All possible outcomes:

\begin{array}{cccccc}1,1&1,2&1,3&1,4&1,5&1,6\\2,1&2,2&2,3&2,4&2,5&2,6\\3,1&3,2&3,3&3,4&3,5&3,6\\4,1&4,2&4,3&4,4&4,5&4,6\\5,1&5,2&5,3&5,4&5,5&5,6\\6,1&6,2&6,3&6,4&6,5&6,6\end{array}

Here, the first number is the number on the 1st die and the second number is the number on the 2nd die.

There are 36 possible outcomes.

A total of 4 give outcomes:

1,3\\2,2\\3,1

So, there are 3 favorable outcomes.

The probability of getting a total of 4 is

\dfrac{3}{36}=\dfrac{1}{12}

You might be interested in
4x<br>f(x)=<br>x -3 togetherness​
frozen [14]

Answer:

f(x)=2(\dfrac{2}{3})^x.

Step-by-step explanation:

f(x)=1/2(2)xf(x)=3/4(-1/5)xf(x)=(7/2)xf(x)=2(2/3)x

3 0
4 years ago
An adjustable ladder on the back of the firetruck is needed for firefighters to climb to very high buildings. The maximum angle
torisob [31]
Cos 70 = horizontal distance /
 100 horizontal distance = 100 cos 70  = 32.2feet
3 0
3 years ago
Se tiene la sucesión 3, 8, 13, 18, 23 … ¿Cuáles son los siguientes dos términos y cuál es la regla general?
V125BC [204]

Respuesta:

28; 33

A (n) = 5n - 2

Explicación paso a paso:

A partir de los datos dados, 3, 8, 13, 18, 23…, podemos ver que cada valor sucesivo de la serie aumenta en 5;

Por lo tanto, los siguientes dos términos de la serie deberían ser:

23 + 5 = 28

28 + 5 = 33

La serie es una progresión aritmética:

Recuerde la fórmula general:

A (norte) = a + (norte - 1) d

Donde, a = Primer término = 3; d = diferencia común = 5

n = enésimo término

A (n) = 3 + (n-1) 5

A (n) = 3 + 5n - 5

A (n) = 5n - 2

6 0
4 years ago
Seb bought 2 apples and 3 pears.
ryzh [129]
2a + 3p = 1.59

a = 0.24

Plug it in our equation:

2(0.24) + 3p = 1.59

Multiply:

0.48 + 3p = 1.59

Subtract 0.48 to both sides:

3p = 1.11

Divide 3 to both sides:

p = 0.37

So one pair costs <span>£0.37</span>
5 0
3 years ago
How can I tell, when doing synthetic division, if the binomial is<br> a FACTOR of the dividend?
Alecsey [184]

If you get 0 as the last value in the bottom row, then the binomial is a factor of the dividend.

Let's say the binomial is of the form (x-k) and it multiplies with some other polynomial q(x) to get p(x), so,

p(x) = (x-k)*q(x)

If you plug in x = k, then,

p(k) = (k-k)*q(k)

p(k) = 0

The input x = k leads to the output y = 0. Therefore, if (x-k) is a factor of p(x), then x = k is a root of p(x).

It turns out that the last value in the bottom row of a synthetic division table is the remainder after long division. By the remainder theorem, p(k) = r where r is the remainder after dividing p(x) by (x-k). If r = 0, then (x-k) is a factor, p(k) = 0, and x = k is a root.

5 0
3 years ago
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