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cestrela7 [59]
3 years ago
10

The dimensions of Sara's apartment are22 1/2 feet by 25 feet. In the scale drawing below,1 1/2 inches is equivalent to 15 feet.

What is the unit rate
Mathematics
1 answer:
expeople1 [14]3 years ago
7 0

Answer:

Step-by-step explanation:

Given:

The scale 1 1/2 (\frac{3}{2}) inches = 15 feet

<=>  1 inch = \frac{15 feet}{\frac{3}{2} } = 10 feet.

<=> 1 feet = \frac{1}{10} inch

The dimensions of Sara's apartment are 22 1/2  (\frac{45}{2}) feet by 25 feet, so the new dimensions of Sara's apartment by inches are:

  • (\frac{45}{2}) feet = \frac{45}{2} * \frac{1}{10} = \frac{9}{4} inches
  • 25 feet = 25*\frac{1}{10} = \frac{5}{2} inches

Hope it will find you well.

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Please need help from math experts!!!! Struggling so hard…
Alenkinab [10]

Answer:

Step-by-step explanation:

A(10,10)      B(b,10b)

ax-2y=30

a)\\a(10)-2(10)=30\\10a-20=30\\10a-20+20=30+20\\10a=50

Divide both parts of the equation by 10:

a=5

Hence,

5x-2y=30

5(b)-2(10b)=30

5b-20b=30

-15b=30

Divide both parts of the equation by -15:

b=-2

Thus,

a=5     b=-2

b)\\A(10,10)\ \ \ \ \ \ B(-2,-20)\\ \displaystyle\\C(x_C,y_C)=(\frac{10+(-2)}{2} ,\frac{10+(-20)}{2} )\\\\C(x_C,y_C)=(\frac{10-2}{2},\frac{10-20}{2} )\\\\C(x_C,y_C)=(\frac{8}{2}  ,\frac{-10}{2})\\\\C(x_C,y_C)=(4,-5)\\Hence,\ C(4,-5)

5x-2y=30\\5x-2y+2y=30+2y\\5x=30+2y\\5x-30=30-30+2y\\5x-30=2y\\

Divide both parts of the equation by 2:

2.5x-15=y

c)\\y=2.5x-15

               The equation of the perpendiqular bisector

                              \boxed {y=-\frac{x}{k} +b}  

Hence,

\displaystyle\\y=-\frac{x}{2.5}-15 \\\\y=-0.4x-15

5 0
2 years ago
Use the graph to determine the domain and range of the relation and wether the relation is a function
valentinak56 [21]

Answer:

C. Domain: {x|-8\le x\le8}, Range: all real numbers;No, it is not a function

Step-by-step explanation:

From the diagram in the attachment, the domain is  {x|-8\le x\le8}.

The reason is that, the furthest the graph could extend is 8 to the right and left of the y-axis.

The range of the relation is all real numbers. The reason is that, the graph extends up above and below the x-axis without bounds.

The relation is not a function, because its graph failed the vertical line test.

See graph

The correct answer is C.

6 0
3 years ago
What is the discriminant of the quadratic equation 4x^2-7x-6=04x 2 −7x−6=0?
Wittaler [7]

Answer:

  145

Step-by-step explanation:

The discriminant of quadratic ...

  ax^2 +bx +c = 0

is ...

  d = b^2 -4ac

For your quadratic, you have a=4, b=-7, c=-6, so the discriminant is ...

  d = (-7)^2 -4(4)(-6) = 49 +96 = 145

The discriminant is 145.

7 0
4 years ago
(w+3/w+4)=(w-1/w+7)+1
RoseWind [281]
I hope this helps you

5 0
3 years ago
Solve (t-5) = 2 where t is a real number.<br> Simplify your answer as much as possible.
In-s [12.5K]

Answer:

7

Step-by-step explanation:

T-5=2 2+5=7

7 0
4 years ago
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