Answer: 2
Step-by-step explanation:
5-3=2
30-5=15
-2x -9y = -25
-(-4x -9y =-23)
2x = -2
x = -1
-2(-1) -9y = -25
2 - 9y = -25
-9y = -25 -2
-9y = -27
y = 3
(-1,3)
Answer:
4032 different tickets are possible.
Step-by-step explanation:
Given : At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the first two races. If the first race runs 9 horses and the second runs 8.
To find : How many different tickets are possible ?
Solution :
In the first race there are 9 ways to pick the winner for first and second place.
Number of ways for first place - 
Number of ways for second place - 
In the second race there are 8 ways to pick the winner for first and second place.
Number of ways for first place - 
Number of ways for second place - 
Total number of different tickets are possible is


Therefore, 4032 different tickets are possible.