H'(x) = 2f'(x)
h'(1) = 2*f'(1) = 2*4
h'(1) = 8
Answer:
a)6x = 16
Step-by-step explanation:
<h2><u>Finding the value</u></h2>
the ratio can be solved by <u>cross multiplication :</u>
6 : 2
8 : x
6*x = 8*2
6x = 16
answer is : <u>a) 6x = 16</u>
With 5 elements in A={20,1,6,10,11}, there are 2^5=32 possible subsets, including
the null set, and A itself.
Any subset that is identical to A is NOT a proper subset.
Therefore there are 31 proper subsets, plus the subset {20,1,6,10,11}.
The subsets are:
null set {} (has no elements) ........total 1
{20},{1},{6},{10},{11}.......................total 5
{20,1},{20,6}...{10,11}.....................total 10
{20,1,6},{20,1,10},...{6,10,11}.........total 10
{20,1,6,10}...{1,6,10,11}.................total 5
{20,1,6,10,11}.................................total 1
Altogether 32 subsets.
