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3 years ago

Ok ong i'm struggling and need help i've been up all night- Ill give brainlyest!!

Mathematics

1 answer:

Ipatiy [6.2K]3 years ago

3 0

Answer:

Step-by-step explanation

- 7(6x-1)+x=36

=> 42x - 7 + x = 36
=> 43x - 7 = 36
=> 43x = 36 + 6 = 43
=> x = 43 / 43 = 1

- 11-2(8+3p)=7²

=> 11 - 16 - 6p = 7^2
=> 11 - 16 - 6p = 49
=> -5 - 6p = 49
=> -6p = 49 + 5 = 54
=> p = (54) / (-6) = - 9

- 1/4(5b+11)=19

=> (5/4)b + (11/4) = 19
=> (5/4)b = 19 - (11/4) = 65 /4
=> b = (65/4) / (5/4) => (65/4) * (4/5) = 13

- 2/7(4m-18)=12

=> (8/7)m - (36/7) = 12
=> (8/7)m = 12 + (36/7) = 120/7
=> m = (120/7) / (8/7) = 120 /8 = 15

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Approximate the area between the xxx-axis and h(x) = \dfrac{1}{7-x}h(x)= 7−x 1 h, (, x, ), equals, start fraction, 1, divided

tiny-mole [99]

Answer:

$\dfrac{47}{60}$ sq. units.

Step-by-step explanation:

The given function is

$h(x)=\dfrac{1}{7-x}$

We need to find the area between x-axis and the given function from x=2 to x=5.

Left Riemann sum formula of area:

$Area=\sum_{n=0}^{N-1}f(x_n)(\Delta x_n)$

For given question,

$Area=\sum_{n=2}^{5-1}f(x_n)(\Delta x_n)$

$Area=\sum_{n=2}^{4}f(x_n)(\Delta x_n)$

$Area=f(x_2)(3-2)+f(x_3)(4-3)+f(x_4)(5-4)$

Now,

$Area=\dfrac{1}{7-2}\times (1)+\dfrac{1}{7-3}\times (1)+\dfrac{1}{7-4}\times (1)$

$Area=\dfrac{1}{5}+\dfrac{1}{4}+\dfrac{1}{3}$

$Area=\dfrac{12+15+20}{60}$

$Area=\dfrac{47}{60}$

Therefore, the required area is $\dfrac{47}{60}$ sq. units.

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3 years ago

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beks73 [17]

Answer:

Step-by-step explanation:

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