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2 years ago

Writing in Math Describe a situation in which it would be better

Mathematics

1 answer:

NeTakaya2 years ago

5 0

Answer:

the number 151

Step-by-step explanation:

this because if you round 151 to the nearest hundread it would give you 200 but if you round it to the nearest ten ot would give you 150 which is closer to the actual number than 200.

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What is 11 times 5/6

Inga [223]

Answer:

simplified form -

Exact form - 55/6

Decimal form - 9.16..

Mixed number form - 9 1/6

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.

adoni [48]

Answer: The required derivative is $\dfrac{8x^2+18x+9}{x(2x+3)^2}$

Step-by-step explanation:

Since we have given that

$y=\ln[x(2x+3)^2]$

Differentiating log function w.r.t. x, we get that

$\dfrac{dy}{dx}=\dfrac{1}{[x(2x+3)^2]}\times [x'(2x+3)^2+(2x+3)^2'x]\\\\\dfrac{dy}{dx}=\dfrac{1}{[x(2x+3)^2]}\times [(2x+3)^2+2x(2x+3)]\\\\\dfrac{dy}{dx}=\dfrac{4x^2+9+12x+4x^2+6x}{x(2x+3)^2}\\\\\dfrac{dy}{dx}=\dfrac{8x^2+18x+9}{x(2x+3)^2}$

Hence, the required derivative is $\dfrac{8x^2+18x+9}{x(2x+3)^2}$

3 0

2 years ago

If x = 2.7, 5x = ____. (Input decimals only, such as 12.7.)

lukranit [14]

Answer:

5x=13.5

Step-by-step explanation:

Well, we know that 1x=2.7. So, if we want 5x we need to multiply 2.7*5 becuase 1x=2.7, so 5x=2.7*5.

Multiply. 2.7*5=13.5

So, 5x=13.5.

Hope this helps!

5 0

3 years ago

Read 2 more answers

Working as a team 8 mathletes can solve 20 problems in ten minutes. At this same rate how many mathletes are needed in order to

emmainna [20.7K]

7 is the right answer(please rate 5.0 stars so i can help other people out thanks)

8 0

3 years ago

Read 2 more answers

Round to the nearest hundredth (Geometric Series problem)

WITCHER [35]

Answer:

15.98

Step-by-step explanation:

∑₁¹⁰ $8(\frac{1}{4} )^{n-1}$

$=8[1+\frac{1}{4} +\frac{1}{16} + ........ +t_{10}]$

We have to use the formula of sum of a G.P. series with common ratio r < 1.

If the first term is a, the common ratio is r and the number of terms is n then the sum [a + ar + ar² + ar³ + ......... up to n terms] is given by

$[a \times\frac{1-r^{n} }{1-r}]$

$= 8[1 \times \frac{1-\frac{1}{2^{10} } }{1-\frac{1}{2} } ]$

$= 15.98$ (Answer)

4 0

2 years ago