All categories

3 years ago

The highest scores ata gymnastics meet were 9.675, 9.25,9.325 and 9.5. Write the scores in order from least to greatest.

Mathematics

2 answers:

lapo4ka [179]3 years ago

6 0

Answer with Step-by-step explanation:

The highest scores at a gymnastics meet were:

9.675, 9.25,9.325 and 9.5

We have to write the scores in order from least to greatest.

The number before the decimal place is 9

we will see the numbers after the decimal place and then arrange them

0.25 is the smallest

then comes 0.325

after that 0.5

and at the end 0.675

Hence, Numbers in order from least to greatest is:

9.25, 9.325, 9.5 and 9.675

Inga [223]3 years ago

4 0

Starting with the least score it would be ; 9.25 , 9.325 , 9.5 , 9.675

You might be interested in

Which value is NOT a solution of 8x3 – 1 = 0?

Tpy6a [65]

Note: As you may have unintentionally missed to add the value choices. But, I would make sure to explain the concept so that you may improve your understanding in terms of solving these type of questions.

Answer:

Any value other than the values $x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$ will not be a solution of $8x^3\:-\:1\:=\:0$ .

Step-by-step explanation:

Considering the equation

$8x^3\:-\:1\:=\:0$

Steps to solve the equation

$8x^3-1=0$

$\mathrm{Add\:}1\mathrm{\:to\:both\:sides}$

$8x^3-1+1=0+1$

$\mathrm{Simplify}$

$x^3=\frac{1}{8}$

$\mathrm{Divide\:both\:sides\:by\:}8$

$\frac{8x^3}{8}=\frac{1}{8}$

$\mathrm{Simplify}$

$x^3=\frac{1}{8}$

$\mathrm{For\:}x^3=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}$

$x=\sqrt[3]{\frac{1}{8}},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1+\sqrt{3}i}{2},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1-\sqrt{3}i}{2}$

So,

$x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$

Therefore,

Any value other than the values $x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$ will not be a solution of $8x^3\:-\:1\:=\:0$ .

Keywords: solution, value

Learn more about equation solution from brainly.com/question/1679491

#learnwithBrainly

7 0

3 years ago

The volume of a volleyball is about 288 cubic inches. what is the radius of the volleyball, to the nearest tenth of an inch? use

Len [333]

Answer:

The radius of the volleyball is 8.3 inches

Step-by-step explanation:

Given

$r = \sqrt{\frac{3v}{4\pi}}$