Slove for x 2m-nx=x+4

The distribution of weights of potato chip bags filled off a production line is unknown. However, the mean is m=13.35 OZs and th

Nikitich [7]

Answer:

a) $\mu_{\bar X} =13.35$

e.none of the above

b) $\sigma_{\bar X}= \frac{0.12}{\sqrt{36}}= 0.02$

a.0.0200

c) $z = \frac{13.32-13.35}{\frac{0.12}{\sqrt{36}}}= -1.5$

$P(\bar X< 13.32)= P(z$

a.0.0668

d) $z = \frac{13.30-13.35}{\frac{0.12}{\sqrt{36}}}= -2.5$

$z = \frac{13.36-13.35}{\frac{0.12}{\sqrt{36}}}= 0.5$

$P(13.30$

c.0.6853

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

$X \sim N(13.35,0.12)$

Where $\mu=13.35$ and $\sigma=0.12$

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

Part a

$\mu_{\bar X} =13.35$

Part b

$\sigma_{\bar X}= \frac{0.12}{\sqrt{36}}= 0.02$

Part c

We want this probability:

$P(\bar X< 13.32)$

For this case we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And using this formula we got:

$z = \frac{13.32-13.35}{\frac{0.12}{\sqrt{36}}}= -1.5$

$P(\bar X< 13.32)= P(z$

Part d

We want this probability:

$P(13.30$

For this case we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And using this formula we got:

$z = \frac{13.30-13.35}{\frac{0.12}{\sqrt{36}}}= -2.5$

$z = \frac{13.36-13.35}{\frac{0.12}{\sqrt{36}}}= 0.5$

$P(13.30$

8 0

3 years ago

Ok please help me!!!!!!!

docker41 [41]

Answer:

keep it a bean bro I can't even see the question

Step-by-step explanation:

7 0

2 years ago

Show work Find the volume of the pyramid

Burka [1]

Hello there, and thank you for posting your question here on brainly.

______________________________________________________________
Answer: 128
Why?
______________________________________________________________
To find the volume of a cylinder, we have to use the formula lwh/3. The length is 8, width is 4, and height is 12. So we have to multiply all of those together, then divide by 3. (8 * 4 = 32) -> (32 * 12 = 384) -> (384/3 = 128) The volume is 128.

Hope this helped you! ♥

3 0

3 years ago

What is the simplified form of each expression? a. (6 + 3)2 − 4 b. 23 + (14 − 4) ÷ 2

liraira [26]

Answer:

a. 14

b. 28

Step-by-step explanation:

a. ex: (6+3)2 - 4 = 9(2) - 4

18 - 4 = 14

b. ex: 23 + (14 - 4) / 2

Use PEMDAS

P 1st

10

D over A

5

A

28

Hope this helps!

5 0

2 years ago

Use a table to show the sample space of two-digit numbers using the digits 1,4,5,9. Use the column label as the tens digit and t

Lesechka [4]

Answer:

19

Step-by-step explanation:

7 0

2 years ago