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viktelen [127]
3 years ago
5

Pls help due in a few mins

Mathematics
2 answers:
My name is Ann [436]3 years ago
5 0
Number 2 is 4. Hope this helped
kolbaska11 [484]3 years ago
3 0
Option 4 is the correct answer for number 2
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Calculate the midpoint between (2,-5) and (4, -7).
balandron [24]

The midpoint between (2,-5) and (4, -7)  is Option D.(3-6)

Step-by-step explanation:

Given:

Points (2,-5) and (4, -7)

To Find:

Midpoint of the points=?

Solution:

The midpoint that lies between the two points is given by

(x_m, y_m) = (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

Where

(x_m, y_m)= coordinates of the midpoint

(x_1, y_1)= coordinates of the first point

(x_2, y_2)= coordinates of the second point

we have,

x_1= 2

y_1= -5

x_2= 4

y_2= -5

Substituting the values in the mid point formula,

(x,y)=(\frac{(2+4)}{2},\frac{(-5-7)}{2})

(x,y)=(\frac{(6)}{2},\frac{(-12)}{2})

(x,y)=(3,-6)

5 0
4 years ago
Use a calculator to solve for xin the equation 2e^3x = 400. Round your answer to<br> three decimals.
Paul [167]

the answer is

D. 1.766
3 0
4 years ago
Solving multi step Equations
Snowcat [4.5K]

Hello there!


2(x + 5) = 3x + 1

You want to start with the distribution property

(2)(x) + (2)(5) = 3x + 1

2x + 10 = 3x + 1

2x - 3x = 1 - 10

-x = -9

Multiply by -1 to remove the negative sign

x = 9



3y - 4 = 6 - 2y

3y + 2y = 6 + 4

5y = 10

y = 10/5


As always, it is my pleasure to help student like you.

5 0
4 years ago
What is 2 times pi times r?<br> pi is 3.14 or 22/7.<br> What is r?
Ludmilka [50]
"2 times pi times r", which can be written as "2*pi*r", represents the circumference of a circle. This is the distance around the circle (aka perimeter)

r is the radius of the circle

if you know the diameter then you can divide the diameter in half to get the radius (example: diameter is 10 so the radius is 5)
7 0
3 years ago
Read 2 more answers
The fraction 5/8<br> produces a repeating decimal.<br> ___<br> 0.625<br><br> True or False
Rama09 [41]

Answer:

False i just did it

Step-by-step explanation:

7 0
3 years ago
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