Answer:
hiii <33
Step-by-step explanation:
Answer:
B. A cow of 5 years is predicted to produce 5.5 more gallons per week.
Step-by-step explanation:
Let , where is the age of the dairy cow, measured in years, and is the predicted milk production, measured in gallons per week.
Besides, we consider and , such that , we define the difference between predicted milk productions () below:
(1)
If we know that and , then the difference between predicted milk productions is:
That is, a cow of 5 years is predicted to produce 5.5 more gallons per week than a cow of 10 years. Hence, the right answer is B.
Given:
μ = 25 mpg, the population mean
σ = 2 mpg, the population standard deviation
If we select n samples for evaluation, we should calculate z-scores that are based on the standard error of the mean.
That is,
The random variable is x = 24 mpg.
Part (i): n = 1
σ/√n = 2
z = (24 -25)/2 = -0.5
From standard tables,
P(x < 24) = 0.3085
Part (ii): n = 4
σ/√n = 1
z = (24 -25)/1 = -1
P(x < 24) = 0.1587
Part (iii): n=16
σ/√n = 0.5
z = (24 - 25)/0.5 = -2
P(x < 24) = 0.0228
Explanation:
The larger the sample size, the smaller the standard deviation.
Therefore when n increases, we are getting a result which is closer to that of the true mean.
You could do:
1 mile : 1,760 yards.
So, you would multiply 1790 times 2 and get 3520. The closest thing to 4500 yards is 3520.
So you get 2 miles and 980 yards.
The answer is 1/4 or 0.25.
steps:
first look in the parenthesis and notice that the denominator is not the same. set the denominator to 6 for the fraction 1/3 by multiplying 3(2) and 1(2) which makes the fraction 1/6. now add -5/6 and 1/6 inside the parenthesis. you should get -3/6 which you should put in the simplest form: -1/2. now combine -1/2 and -1/2 to get 1/4