A triangle has the following two angle measures:

Mathematics

1 answer:

Vitek1552 [10]2 years ago

5 0

Answer:

62°

Step-by-step explanation:

Given that the triangle has two angle measures of 41° and 77°.

All the angles in a triangle must add up to 180° (e.g. 20° + 60° + 100°). So we write a simple equation to solve for the mystery angle measure:

Let x = the missing measure

$41 + 77 + x = 180$

Now that we have our equation, let's start solving it. First, we need to add 41 and 77 together which simplifies the equation: $118 + x = 180$

Then we subtract 118 from both sides to isolate x - this will give us the value of this variable: $x = 62$

Therefore, the third angle must have a measure of 62°.

You might be interested in

sammy counted peanuts in several packages of roasted peanuts. He found that the bags had 102, 114, 97, 85, 106, 120, 107, and 11

zmey [24]

Probably a for plot, because It shows how close each value is, or if the values are all scattered around. it gives you a more accurate ways of seeing how close the data is. hope this helped

6 0

3 years ago

PLEASE HELP, THIS IS REALLY IMPORTANT. PLEASE ANSWER ASAP.

Assoli18 [71]

Yes the diagonals of a parallelogram have the same midpoint since they ... of the intersection of the diagonals of parallelogram AB CD given the vertex points ... If a parallelogram is a rhombus then its diagonals are? , statement 2 is the answer

8 0

2 years ago

Can someone PLEASE solve this quadratic equation by factoring with the steps? :(

salantis [7]

Answer:

There are no simple factors to this expression. You can however solve for x, giving you:

x = -1 ± √(y + 3)

Step-by-step explanation:

There is no simple pair of factors to this equation, so we'll have to go through the full process. You can see that by observing that there is no pair of rational numbers that add to make 2 and multiply to make -2. We can however solve for x:

$y = x^2 + 2x - 2\\y + 2 = x^2 + 2x\\y + 3 = x^2 + 2x + 1\\y + 3 = (x + 1)^2\\(x + 1)^2 = y + 3\\x + 1 = \pm \sqrt{y + 3}\\x = -1 \pm \sqrt{y + 3}$