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pychu [463]
3 years ago
9

9x+12x-21=27 How do I solve ?

Mathematics
1 answer:
alexandr402 [8]3 years ago
6 0
You gotta combine like terms which would be 9x and 12x which gives you 21x .

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Help me plz asap i need the first question dont answer till u see file
nika2105 [10]
Okay, so with the link we can tell this:

flour and baking soda are equal ratios
salt is one half the ratio of flour/baking soda

A: correct
flour and baking soda as equal ratios

B: incorrect
salt is at an incorrect ratio to flour

C: correct 
salt is at a correct ratio to baking soda

D: incorrect
salt is at an incorrect ratio to baking soda

E: correct
baking soda is at a correct ratio to salt

answers: A, C , E
8 0
3 years ago
Multiply: 0.27055 · 1,000
photoshop1234 [79]

0.27055*1,000=

270.55

-Hunter

4 0
3 years ago
Read 2 more answers
Write each exponential expression as a decimal.
HACTEHA [7]
1. 100 2. 1000 3. 100000 4. 10000000 here is the first part

8 0
3 years ago
A line has a slope of 2 and passes through the point ( -1, 3). Write an equation in slope intercept form
stealth61 [152]

Answer:

y=2x+5

Step-by-step explanation:

The equation of a line in slope intercept form is written as: y=mx +b where m is the slope and b is the y-intercept.

Taking point (-1,3) , m= 2 and imaginary point on the line, (x,y) then ;

m=change is y-coordinates/change in x-coordinate

m=Δy/Δx

m=y-3/x--1

2= y-3 / x+1

2(x+1) = y-3

2x +2 =y-3

2x=y-3-2

2x=y-5

<u>y=2x+5 is the equation.</u>

7 0
4 years ago
Sketch the region enclosed by y=3x and y=x^2 . Then find the area of the region.
kolezko [41]

Answer:

A=4.5u^2

Step-by-step explanation:

The integral of a function gives you the area under the curve, the subtraction of one of the areas from the other will give you the area in between.

The limits of integration are the points where the curves intersect each other(take the curves has a system of equation and solve for x and y):

y=3x, y=x^2\\3x=x^2\\x^2-3x=0\\x(x-3)=0\\x_1=0\\x-3=0\\x_2=3

y_1=3x_1=3(0)=0\\y_2=3x_2=3(3)=9

The integral will be the subtraction of the curve y=3x and y=x^2  (In the graph you can see y=3x is the upper curve):

\int\limits^3_0 {3x-x^2} \, dx =\left\frac{3x^2}{2}-\frac{x^3}{3}\right|^3_0=\frac{3(3)^2}{2}-\frac{(3)^3}{3}-\left(\frac{3(0)^2}{2}-\frac{(0)^3}{3}\right)\\\int\limits^3_0 {3x-x^2} \, dx =\frac{27}{2}-\frac{27}{3} =13.5-9=4.5u^2

6 0
3 years ago
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